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biroo88
New Member

Count services that occur during same time frame

Hello,

 

I am trying to get a count of services recieved per person_id that cross time frames.  I am getting counts, but unsucessfully getting the intended result. For example, 1001013321 should only be a value of 1 since the enrollements did not cross dates. Any help would be appreicated in detereming the correct calculation to find the number of enrollements occuring at the same time for a person. 

 

biroo88_0-1677165027671.png 

biroo88_1-1677165140148.png

 

 

1 ACCEPTED SOLUTION
v-stephen-msft
Community Support
Community Support

Hi @biroo88 ,

 

You can try the following measure:

Measure =
CALCULATE (
    COUNT ( 'Table'[ServiceCategory_ID] ),
    FILTER (
        ALLSELECTED ( 'Table' ),
        [Person_ID] = MAX ( 'Table'[Person_ID] )
            && [ServiceCategoryReceviedEndDate]
                = MAX ( 'Table'[ServiceCategoryReceviedEndDate] )
            && [ServiceCategoryReceviedStartDate]
                = MAX ( 'Table'[ServiceCategoryReceviedStartDate] )
    )
)

vstephenmsft_0-1677466870995.png

                                                                                                                                                         

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.           

View solution in original post

1 REPLY 1
v-stephen-msft
Community Support
Community Support

Hi @biroo88 ,

 

You can try the following measure:

Measure =
CALCULATE (
    COUNT ( 'Table'[ServiceCategory_ID] ),
    FILTER (
        ALLSELECTED ( 'Table' ),
        [Person_ID] = MAX ( 'Table'[Person_ID] )
            && [ServiceCategoryReceviedEndDate]
                = MAX ( 'Table'[ServiceCategoryReceviedEndDate] )
            && [ServiceCategoryReceviedStartDate]
                = MAX ( 'Table'[ServiceCategoryReceviedStartDate] )
    )
)

vstephenmsft_0-1677466870995.png

                                                                                                                                                         

Best Regards,

Stephen Tao

 

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.           

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