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Hello,
My data :
Player id
A 1
A 2
B 1
C 1
C 3
I want to have the number of id which is identical to all the players which are selected by a filter. For example if I select A, the value is 2, if I also select B the value is 1 and if I select all three players the value is only 1 because there is only the id 1 which is common.
I try to count with a measure the number of common IDs between all the players but I cannot find the right formula.
Thanks
Solved! Go to Solution.
Hi, @Jeremy19 ;
You could try it.
count =
var _playnum=CALCULATE(DISTINCTCOUNT('Table'[Player]),ALLSELECTED('Table'))
var _countall=SUMX( SUMMARIZE('Table',[Player],[id],"1", IF(_playnum= CALCULATE(COUNT('Table'[id]),FILTER(ALLSELECTED('Table'),[id]=MAX('Table'[id]))),1,0)),[1])
return
DIVIDE(_countall ,_playnum)
The final output is shown below:
Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, @Jeremy19 ;
You could try it.
count =
var _playnum=CALCULATE(DISTINCTCOUNT('Table'[Player]),ALLSELECTED('Table'))
var _countall=SUMX( SUMMARIZE('Table',[Player],[id],"1", IF(_playnum= CALCULATE(COUNT('Table'[id]),FILTER(ALLSELECTED('Table'),[id]=MAX('Table'[id]))),1,0)),[1])
return
DIVIDE(_countall ,_playnum)
The final output is shown below:
Best Regards,
Community Support Team_ Yalan Wu
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Try this. @Jeremy19
Count of common IDs = CALCULATE(COUNTROWS(FILTER(SUMMARIZE('TABLE','TABLE'[ID],"duplicates',CALCULATE(COUNTROWS('TABLE'))),[duplicates]>1)))
thingsclump
Hi @Jeremy19
try it, modify the Table name and Column name accordingly
count_num =
VAR CurPlayer =VALUES('Table1'[Player])
VAR CurCount=COUNTROWS(CurPlayer)
VAR TI=FILTER(Table1,Table1[Player] IN CurPlayer)
VAR T2=GROUPBY(TI,Table1[id],"Players",COUNTAX(CURRENTGROUP(),[Player]))
RETURN
COUNTROWS(FILTER(T2,[Players]=CurCount))