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jthomson's avatar
jthomson
Icon for Solution Sage rankSolution Sage
9 years ago
Solved

Count instances of string in multiple columns

Hi,

 

Been searching the forums but can't find anything that exactly replicates what I'm trying to do - I currently have an Excel file that has the following column names (along with various others which I will want to slice on later, but doesn't affect this calculation) and some basic sample data:

 

Hire Request Date - Hirer 1 - Hirer 2 - Hirer 3 - Hirer 4

1/1/2017 - Bob - (blank) - (blank) - (blank)

1/1/2017 - Alice - Bob - (blank) - (blank)

2/1/2017 - (blank) - Bob - Clive - (blank)

3/1/2017 - Clive - (blank) - Bob - (blank)

 

The four hirer columns are populated either by a hirer name (of which there's around 20 possibilities which apply to every column, I have a separate table listing them all related to hirer 1 as active and the other hirer columns as inactive), or are blank, and more than one column can be non-blank at the same time in any given row. Very simply, I want to be able to count the total number of times each hirer appears in all the columns, so the expected results here would be Bob 4, Alice 1, Clive 2. In Excel this is just four countifs, but while I can get one column to work fine using counta (although it returns blanks as an option, which I don't want), if I try to add two or more of the columns together, it breaks down and provides wildly incorrect results. Any suggestions on how I can make progress on this?

Need Help
  • Vvelarde's avatar
    Vvelarde
    9 years ago

    jthomson

     

    Hi try with this:

     

    CountinAllHirerColumns =
CALCULATE (
    COUNTROWS ( Table1 ),
    USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 1] )
)
    + CALCULATE (
        COUNTROWS ( Table1 ),
        USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 2] )
    )
    + CALCULATE (
        COUNTROWS ( Table1 ),
        USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 3] )
    )

    After that in your visual filter:

     

     

    Regards

     

    Victor

    Lima - Peru

5 Replies

  • Vvelarde's avatar
    Vvelarde
    Icon for Community Champion rankCommunity Champion
    9 years ago

    jthomson

     

    Hi try with this:

     

    CountinAllHirerColumns =
CALCULATE (
    COUNTROWS ( Table1 ),
    USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 1] )
)
    + CALCULATE (
        COUNTROWS ( Table1 ),
        USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 2] )
    )
    + CALCULATE (
        COUNTROWS ( Table1 ),
        USERELATIONSHIP ( HirerTable[Hirer], Table1[Hirer 3] )
    )

    After that in your visual filter:

     

     

    Regards

     

    Victor

    Lima - Peru

    • YashGurudath891's avatar
      YashGurudath891
      Regular Visitor
      7 years ago

      Would you happen to have an idea what to do if there were 700+ Columns? In my case, I am looking for specific string in all these columns.
      I can get the Results in excel by doing COUNTIF(A1:A700,"PASS") and it gives me the total count.
      Please let me know if there is a solution to this. Vvelarde 

       

      Thanks in Advance

      • Ashish_Mathur's avatar
        Ashish_Mathur
        Icon for Super User rankSuper User
        7 years ago

        Hi,

        In your text, you state 700+ columns but in your formula you have 700 rows.  Please clarify.  If there are 700 columns, you may have to Unpivot columns and then it becomes an easy one to solve.

        Share some data and show the expected result.

    • Anonymous's avatar
      Anonymous
      Not applicable
      6 years ago

      Vvelarde 

      Hi, adding to that, can this be used for dynamic number of Hirer columns in Table1?

  • v-huizhn-msft's avatar
    v-huizhn-msft
    Icon for Microsoft Employee rankMicrosoft Employee
    9 years ago

    Hi jthomson,

    After research and test, the Vvelarde solution is solid. Please folllow and mark the right reply as answer. And I am glad to help you if you still have any problems.

    Best Regards,
    Angelia