Forum Discussion
Count dates between two dates excluding dynamic days
- 6 years ago
Hi Anonymous ,
Please refer to the following measure:
Measure = VAR days = DATEDIFF ( MAX ( 'Table'[DataInicio] ), MAX ( 'Table'[DataFim] ), DAY ) + 1 VAR selected_dates = ADDCOLUMNS ( GENERATESERIES ( MAX ( 'Table'[DataInicio] ), MAX ( 'Table'[DataFim] ) ), "Weekday", WEEKDAY ( [Value], 3 ) ) VAR mcount = IF ( MAX ( 'Table'[Monday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 0 ) ), 0 ) VAR tcount = IF ( MAX ( 'Table'[Tuesday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 1 ) ), 0 ) VAR wcount = IF ( MAX ( 'Table'[Wednesday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 2 ) ), 0 ) VAR Tucount = IF ( MAX ( 'Table'[thursday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 3 ) ), 0 ) VAR fcount = IF ( MAX ( 'Table'[friday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 4 ) ), 0 ) VAR sacount = IF ( MAX ( 'Table'[saturday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 5 ) ), 0 ) VAR suncount = IF ( MAX ( 'Table'[sunday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 6 ) ), 0 ) RETURN ( days - ( mcount + tcount + wcount + Tucount + fcount + sacount + suncount ) )If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Best Regards,
Dedmon Dai
Hi Anonymous ,
Create a new Column
This will give you the sum of False Days
Column =
VAR _mon =
IF (
'Table'[Monday]
= TRUE (),
1,
0
)
VAR _tue =
IF (
'Table'[Tuesday]
= TRUE (),
1,
0
)
VAR _wed =
IF (
'Table'[Wednesday]
= TRUE (),
1,
0
)
VAR _thur =
IF (
'Table'[thursday]
= TRUE (),
1,
0
)
VAR _fri =
IF (
'Table'[friday]
= TRUE (),
1,
0
)
VAR _sat =
IF (
'Table'[saturday]
= TRUE (),
1,
0
)
VAR _sun =
IF (
'Table'[sunday]
= TRUE (),
1,
0
)
VAR _suum = _mon + _tue + _wed + _thur + _fri + _sat + _sun
RETURN
7 - _suum
Subtract this with the measure you have created below Days Off.
Regards,
Harsh Nathani
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Hi Anonymous ,
Thanks for your reply. I Think I need a measure/column that calculate how many "Falses" I've in the period between my DataInicio and DataFim.
Example,
In my ID 2, I've 15 days (18/05/2019 - 01/06/2019) and in this 15 days, I need to calculate how many Monday, Tuesday and sunday (My falses) exists in this period.
In this period of time I've 6 matchs, because in may the day 19 is sunday, 20 (monday), 21 (tuesday), 26 (sunday), 27 (monday) and 28 (tuesday), So then I will calculate 15-6 = 9days available
With your calculated column I only get how many falses I've by ID
Thnks,
Regards
- v-deddai1-msft6 years agoCommunity Support
Hi Anonymous ,
Please refer to the following measure:
Measure = VAR days = DATEDIFF ( MAX ( 'Table'[DataInicio] ), MAX ( 'Table'[DataFim] ), DAY ) + 1 VAR selected_dates = ADDCOLUMNS ( GENERATESERIES ( MAX ( 'Table'[DataInicio] ), MAX ( 'Table'[DataFim] ) ), "Weekday", WEEKDAY ( [Value], 3 ) ) VAR mcount = IF ( MAX ( 'Table'[Monday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 0 ) ), 0 ) VAR tcount = IF ( MAX ( 'Table'[Tuesday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 1 ) ), 0 ) VAR wcount = IF ( MAX ( 'Table'[Wednesday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 2 ) ), 0 ) VAR Tucount = IF ( MAX ( 'Table'[thursday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 3 ) ), 0 ) VAR fcount = IF ( MAX ( 'Table'[friday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 4 ) ), 0 ) VAR sacount = IF ( MAX ( 'Table'[saturday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 5 ) ), 0 ) VAR suncount = IF ( MAX ( 'Table'[sunday] ) = "False", COUNTROWS ( FILTER ( selected_dates, [Weekday] = 6 ) ), 0 ) RETURN ( days - ( mcount + tcount + wcount + Tucount + fcount + sacount + suncount ) )If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Best Regards,
Dedmon Dai
- Anonymous6 years agoNot applicable
- v-deddai1-msft6 years agoCommunity Support
Hi Anonymous ,
Would you please consider Accept it as the solution to help the other members find it more quickly.
Best Regards,
Dedmon Dai