Forum Discussion
DYY94
3 years agoHelper I
Convert Measure into a column
Hello Community,
- I want to duplicate rows by Code_ISIN for each dates.
- Each date in a row with the same Code_ISIN.
NB: Dates it's a measure !
So I thought to convert the Measure 'dates' into column first !
Any Ideas ?
This is my measure :
dates =
VAR str = SELECTCOLUMNS(BTA_Output,"d",BTA_Output[Maturite])&"-"&[MR/365]
VAR _date =
FORMAT (SELECTCOLUMNS(BTA_Output,"d",BTA_Output[Maturite]), "yyyy/mm/dd" )
VAR _num =
[MR/365]
VAR _cal =
"-"
VAR tmp =
FILTER (
ALL ( 'Date' ),
YEAR ( [Date] )
> YEAR ( _date ) - _num
&& YEAR ( [Date] ) < YEAR ( _date )
&& MONTH ( [Date] ) = MONTH ( _date )
&& DAY ( [Date] ) = DAY ( _date )
)
VAR _a =
CONCATENATEX ( tmp, [Date], "
" )
RETURN
SWITCH ( TRUE (), _cal = "-", _a )Output:
Thanks !
2 Replies
- daXtremeSolution Sage
I don't know what it is you want... but this code
FILTER ( ALL ( 'Date' ), YEAR ( [Date] ) > YEAR ( _date ) - _num && YEAR ( [Date] ) < YEAR ( _date ) && MONTH ( [Date] ) = MONTH ( _date ) && DAY ( [Date] ) = DAY ( _date ) )will most likely break on leap years... since February has variable number of days, not always the same.
By the way, measures are dynamic and react to selections. Columns are always static, so I don't quite get how you want to make a measure into a column...