Forum Discussion
Check if a value appears earlier in a column
Hi All
I have a table where one column specifies the week as 1, 2, 3 etc. Another column specifies a job by specific code i.e. ABC-123, ABC-578, CCA-246 etc.
I want to create a new column which states that a job is new if the code does not occur in the first week. Does anyone have any advice on how to do this as I am drawing a blank.
Thanks
LilMurph
LilMurph , first week or last week
A new column =
var _cnt = countx(filter(Table, [Job] =earlier([Job]) && [Week] =1 ), [Job])
return
if(isblank(_cnt), "New", "Old")
based on last week
A new column =
var _cnt = countx(filter(Table, [Job] =earlier([Job]) && [Week] =earlier([Week]) -1 ), [Job])
return
if(isblank(_cnt), "New", "Old")
2 Replies
- amitchandak
Super User
LilMurph , first week or last week
A new column =
var _cnt = countx(filter(Table, [Job] =earlier([Job]) && [Week] =1 ), [Job])
return
if(isblank(_cnt), "New", "Old")
based on last week
A new column =
var _cnt = countx(filter(Table, [Job] =earlier([Job]) && [Week] =earlier([Week]) -1 ), [Job])
return
if(isblank(_cnt), "New", "Old")
- AnonymousNot applicable
Hi LilMurph ,
May I ask if your problem has been solved? Did amitchandak's post above help you? If any of the posts are helpful, then please consider accepting it as a solution to help other members find it faster. Many thanks!
If this doesn't work for you, would you mind providing some data that does not contain private information?
It makes it easier to give you a solution.
- Sample (dummy dataset) data as text, use the table tool in the editing bar
- Expected output from sample data
- Explanation in words of how to get from 1. to 2.
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Best Regards,
Gao
Community Support TeamIf there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly. If I misunderstand your needs or you still have problems on it, please feel free to let us know. Thanks a lot!
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