Forum Discussion
Change Subtotals
I have the folling Matrix
The Goal is calculated in a measure that summarizes the goal for the day
The Average Result is calculated in a measured that is an average of the results per day
I need the subtotal for goal stay as a sum, but the total for average result to be a sum for all the days instead of the general average.
How can I configure this.
Please advise
Omar Octaviano
- Anonymous5 years ago
You could make use of the function HASONEVALUE(). It checks if the field has only one value or not.
For example,
Average Measure = IF( HASONEVALUE(SampleData[WeekDay]), "Calculate Average", "Calculate Sum Of Average" ) - Anonymous5 years ago
Hi ooctaviano ,
According to your description, I create this data:
Here are the steps you can follow:
1. Create measure.
Goal = SUM('Table'[amount])Average = AVERAGE('Table'[amount])Put into the matrix as:
Average_Result = VAR _NEW = SUMMARIZE('Table','Table'[Weekday],"_AVG",[Average]) return IF(HASONEVALUE( 'Table'[Weekday]),[Average],SUMX(_NEW,[_AVG]) )2. Result:
You can downloaded PBIX file from here.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- AnonymousNot applicable
You could make use of the function HASONEVALUE(). It checks if the field has only one value or not.
For example,
Average Measure = IF( HASONEVALUE(SampleData[WeekDay]), "Calculate Average", "Calculate Sum Of Average" ) - AnonymousNot applicable
Hi ooctaviano ,
According to your description, I create this data:
Here are the steps you can follow:
1. Create measure.
Goal = SUM('Table'[amount])Average = AVERAGE('Table'[amount])Put into the matrix as:
Average_Result = VAR _NEW = SUMMARIZE('Table','Table'[Weekday],"_AVG",[Average]) return IF(HASONEVALUE( 'Table'[Weekday]),[Average],SUMX(_NEW,[_AVG]) )2. Result:
You can downloaded PBIX file from here.
Best Regards,
Liu Yang
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.