Forum Discussion
Category fetching using RANK
We have a list of products and respective calculation. I need to fetch the top 3 categories on the basis of ranking of the products' calculation. Then create 3 separate graphs with top 3 products values, as given below:
Hi Anonymous ,
According to your description, I create a sample.
Here's my solution. For example, your logic for sorting products is total sales.
1.Create a calculated column Rank.
Rank = RANKX ( ALL ( 'Table' ), SUMX ( FILTER ( ALL ( 'Table' ), 'Table'[Category] = EARLIER ( 'Table'[Category] ) ), 'Table'[Sales] ), , DESC, DENSE )Get the rank column.
2.Put date and sales in a column chart, for the best selling, put Rank into the visual filter and select the value is 1.
In the same way, for the 2nd most selling, select the visual filter to 2. For the 3rd most selling, select the visual filter to 3. Get the expected result.
I attach my sample below for reference.
Best Regards,
Community Support Team _ kalyjIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- amitchandakSuper User
Anonymous , best is to use a visual level filter on the rank
Create a rank like this and then use filter
Rankx(allexcept(Table, Table[Product]),[sales],,desc,dense)
- v-yanjiang-msftCommunity Support
Hi Anonymous ,
According to your description, I create a sample.
Here's my solution. For example, your logic for sorting products is total sales.
1.Create a calculated column Rank.
Rank = RANKX ( ALL ( 'Table' ), SUMX ( FILTER ( ALL ( 'Table' ), 'Table'[Category] = EARLIER ( 'Table'[Category] ) ), 'Table'[Sales] ), , DESC, DENSE )Get the rank column.
2.Put date and sales in a column chart, for the best selling, put Rank into the visual filter and select the value is 1.
In the same way, for the 2nd most selling, select the visual filter to 2. For the 3rd most selling, select the visual filter to 3. Get the expected result.
I attach my sample below for reference.
Best Regards,
Community Support Team _ kalyjIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.