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DataVitalizer's avatar
DataVitalizer
Icon for Super User rankSuper User
7 years ago
Solved

Calculating the difference between two dates in Years, Months, and Days

Hi Community,

I am working on a report where I have to calculate the difference between two dates (a specific date, and today) then show the resulat in the following format 00years - 00months - 00days

 

Example:

Date1 - Today()

Date2 - 08/19/2020

Result to show => 1 year, 9 months and 19 days

 

Currently I am using the DATEDIF function inside Excel then importing the result in my Power BI report, but everyday I have to open the exel file in order to get the new update then refresh my report in Power BI.

 

Please is there any DAX fomula that can show the date difference in the above format.

 

Thanks.

Best regards. 

 

Need Help
  • PattemManohar's avatar
    PattemManohar
    7 years ago

    DataVitalizer Oh !! Ok, please try this (Just added two more conditions in the SWITCH statement)

     

    Hopefully, this should fix all your test cases :-) Fingers Crossed !!

     

    Final = 
VAR _Years = FLOOR(YEARFRAC([Date1],[Date2],4),1)
VAR _Months = FLOOR(MOD(YEARFRAC([Date1],[Date2],4),1) * 12.0,1)
VAR _daysinMonth = DAY(EOMONTH([Date1],0))
VAR _days = IF(DAY([Date1])<DAY([Date2]),DAY([Date2])-DAY([Date1]),DAY([Date2])+(_daysinMonth-DAY([Date1])))
VAR _daysFinal =  SWITCH(TRUE(),DAY(EOMONTH([Date1],0)) = _days || DAY(EOMONTH([Date2],0)) = _days,0,_days)

RETURN SWITCH(TRUE(),
             _Years>0 && _Months = 0 && _daysFinal = 0,_Years & " year(s)",
             _Years>0 && _Months>0 && _daysFinal = 0, _Years & " year(s), " & _Months & " month(s) ",
             _Years>0 && _Months >0 && _daysFinal >0, _Years & " year(s), " & _Months & " month(s) " & _daysFinal & " day(s)",
             _Years>0 && _Months = 0 && _daysFinal >0, _Years & " year(s), " & _daysFinal & " day(s)",
             _Months>0 && _daysFinal = 0, _Months & " month(s) ",
             _Months>0 && _daysFinal >0, _Months & " month(s) " & _daysFinal & " day(s)",
             _daysFinal & " day(s)"
             )

16 Replies

  • Greg_Deckler's avatar
    Greg_Deckler
    Icon for Community Champion rankCommunity Champion
    7 years ago

    This measure will do it for that case, might need some testing for other use cases:

     

    Note, for this measure, I created a Date1=TODAY() measure and a Date2=DATE(2020,8,19) measure.

     

    Measure 4 = 
VAR __daysinMonth = DAY(EOMONTH([Date1],0))
VAR __years = DATEDIFF([Date1],[Date2],YEAR) - 1
VAR __months = IF(MONTH([Date1])<MONTH([Date2]),MONTH([Date2])-MONTH([Date1]),12-MONTH([Date1])+MONTH([Date2])-1)
VAR __days = IF(DAY([Date1])<DAY([Date2]),DAY([Date2])-DAY([Date1]),DAY([Date2])+(__daysinMonth-DAY([Date1])))
RETURN __years & " year, " & __months & " months and " & __days & " days"
    • DataVitalizer's avatar
      DataVitalizer
      Icon for Super User rankSuper User
      7 years ago

      Hi Greg_Deckler,

       

      Thank you for your reply, the formula you shared returns the format I was looking for, but when I try to calculate the difference between two dates (date1=(2020;5;1) date2=(2020;5;2)) where the the difference is only 1 day the returned result is totally different  -1 year, 11 months and 1 days.

       

      Thank you in advance.

      • Greg_Deckler's avatar
        Greg_Deckler
        Icon for Community Champion rankCommunity Champion
        7 years ago

        DataVitalizer - Yeah, I figured that would be the case. It's going to take some tweaking. I'll take a look when I have some time. It's an interesting problem.