Forum Discussion
Calculating full-time equivalent (FTE)
- 5 years ago
Your simple exceptions aren't that simple. In the first case you can use the MIN() function, for example
hourstocount = MIN(8,hoursworked)
to cap at 8 (ignoring the fact that you are penalizing the worker for doing more work). For the second scenario use ALL() or ALLSELECTED() or ALLEXCEPT() to modify the filter context inside the computation.
- 5 years ago
Hi jsangerman ,
Try to show values as "Percent of column total". Or create a measure like below.
Measure = DIVIDE ( SUM ( 'Table'[Efforts (hours)] ), CALCULATE ( SUM ( 'Table'[Efforts (hours)] ), ALLEXCEPT ( 'Table', 'Table'[Date], 'Table'[User] ) ) )Best regards
Icey
If this post helps, then consider Accepting it as the solution to help other members find it faster.
Which business question do you need to answer? How many FTEs worked on each project each day/month?
Since each of your employees seems to be a "pure" FTE (working all regular working hours on one of the projects) there's no math to be had for daily employee stats.
- jsangerman5 years agoHelper II
Yes, we're trying to understand how many FTEs are working on each project for a given time period.
There is still math to be done; each person could be working on multiple projects for any time period, from day to month, quarter, and year.