Forum Discussion
rclay78
5 years agoFrequent Visitor
Calculate value based on interval
I am trying to figure out how to calculate a 90 day total grouped by date and SN. I want to create a calculated column [Total Value 90 Days] that adds the [Value] over 90 days based on [SN]. I would ...
- 5 years ago
Hi rclay78 ,
According to your request, I did the following test: whether the created col statistic is a duplicate value. Reference is as follows:Col_ = CALCULATE ( COUNTROWS ( Data ), FILTER ( ALL ( Data ), Data[Value] = EARLIER ( Data[Value] ) && Data[SN] = EARLIER ( Data[SN] ) ) )11 = IF ( CALCULATE ( COUNTROWS ( Data ), FILTER ( Data, Data[SN] = EARLIER ( Data[SN] ) && Data[Date] <= EARLIER ( Data[Date] ) ) ) = 1, BLANK (), IF( CALCULATE ( SUM ( Data[Value] ), FILTER ( Data, Data[SN] = EARLIER ( Data[SN] ) && Data[Date] < EARLIER ( Data[Date] ) - 90 && Data[Date] <= EARLIER ( Data[Date] ) ) ) && Data[Col_]=1 ,BLANK(), CALCULATE ( SUM ( Data[Value] ), FILTER ( Data, Data[SN] = EARLIER ( Data[SN] ) && Data[Date] >= EARLIER ( Data[Date] ) - 90 && Data[Date] <= EARLIER ( Data[Date] ) ) ) ))
Best Regards,
Henry
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v-henryk-mstf
5 years agoCommunity Support
Hi rclay78 ,
According to your request, I did the following test: whether the created col statistic is a duplicate value. Reference is as follows:
Col_ =
CALCULATE (
COUNTROWS ( Data ),
FILTER (
ALL ( Data ),
Data[Value] = EARLIER ( Data[Value] )
&& Data[SN] = EARLIER ( Data[SN] )
)
)11 =
IF (
CALCULATE (
COUNTROWS ( Data ),
FILTER (
Data,
Data[SN] = EARLIER ( Data[SN] )
&& Data[Date] <= EARLIER ( Data[Date] )
)
) = 1,
BLANK (),
IF(
CALCULATE (
SUM ( Data[Value] ),
FILTER (
Data,
Data[SN] = EARLIER ( Data[SN] )
&& Data[Date]
< EARLIER ( Data[Date] ) - 90
&& Data[Date] <= EARLIER ( Data[Date] )
)
) && Data[Col_]=1 ,BLANK(), CALCULATE (
SUM ( Data[Value] ),
FILTER (
Data,
Data[SN] = EARLIER ( Data[SN] )
&& Data[Date]
>= EARLIER ( Data[Date] ) - 90
&& Data[Date] <= EARLIER ( Data[Date] )
)
)
))
Best Regards,
Henry
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.