Forum Discussion
Calculate ratio
Hi,
I need to calculate the ratio of some fields. I have the following data, this is the structure of the data.
| ID | Numbers | Date | Hour |
| 1 | 2 | 05-13-2020 | 10:00 |
| 1 | 1 | 05-13-2020 | 11:00 |
| 2 | 3 | 05-13-2020 | 10:00 |
| 3 | 3 | 05-13-2020 | 10:00 |
| 3 | 1 | 05-13-2020 | 11:00 |
I need to create a new column or measure, don't know whats better to use, to calculate the ratio.
I need the follow numbers
| ID | Ratio |
| 1 | 30% |
| 2 | 30% |
| 3 | 40% |
I can use a measure with SUM('table1'[numbers]) and then use this in a card to show the total numbers. I can also click here in the desktop version to "show percent of grand total" which will give me 100%. When I to this in a table I get the correct numbers as show above.
But I want to show an average of these ratio's and I just can't manage to do this with measure. Because I need the total numbers of a day of all ID together and divide this with the total numbers of the ID itself. In this way you get the ratio of each ID.
I hope someone can help me with this.
6 Replies
You could a default SUM aggregation on Number and use "Show as...Percent of grand total".
Anonymous
Greg_Deckler Thank you for your reply.
I know I can use a percent of grand total, but I want a measure that's calculation the average of all the ratio's of all ID's. And I can't do that with the "percent of grand total" function. Hope you understand my question, sorry for my garbage English.
Hi Anonymous
try a measure
Measure = DIVIDE( CALCULATE(SUM(Table[Numbers]), ALLEXCEPT(Table, Table[ID]) ), CALCULATE(SUM(Table[Numbers]), ALL(Table) ) )
Anonymous
You may use the measure below.
Measure = DIVIDE ( AVERAGEX ( VALUES ( Table1[ID] ), CALCULATE ( SUM ( Table1[Numbers] ) ) ), CALCULATE ( SUM ( Table1[Numbers] ), ALLSELECTED ( Table1[ID] ) ) )Thank you both v-chuncz-msft and az38 . Both of the solutions works with a measure.
Is this formula also possible to use as an extra column instead of a measure?
Anonymous
yes, it should be fine
