Forum Discussion
Calculate Ticket SLA
Hi,
Thanks for responding. Here is the sample data.
Average SLA : Average number of days for all Open tickets and tickets closed in last 30 days based on the date submitted and date closed column.
Open Tickets are all tickets other than Closed ones.
Thanks,
Pinky.
Pinky0404 Hello,
Quick question - How should the final result look like ? Also last 30 days from the (current) today's date ?
- Pinky04048 years ago
Helper III
Hi ,
Thanks for your response. The output should be bascially a trend with date( i get this from the source file export date) on X- axis and the average no. of days for all open tickets plus no. of days for 30 days closed tickets.
I used the below DAX formulas to get this trend which show an average no. of days for all open and closed tickets.
SC = IFERROR(DATEDIFF(Footprint[Date Submitted],Footprint[Date Closed],DAY),Footprint[SO])
SO = Footprint[RD]- Footprint[Date Submitted]
RD = MAX(Footprint[Date])
SLA(closed) = IF(ISBLANK(Footprint[SC]),Footprint[SO],Footprint[SC])
Hope you are clear now!!
Thanks,
Pinky.
- Pinky04048 years ago
Helper III
I feel like i got the soultion. But not sure if it is the right way to do.
Created the below DAx:
1)ALL Open = IF(Footprint[New status]<>"Closed",Footprint[SO])
2)Closed in LAst 30 days = IF((Footprint[Date Closed]> Footprint[RD]-30) && (Footprint[Date Closed]<=Footprint[RD]),"Closed 30 days","Null")
3)Days - Closed(30 days) = IF(Footprint[Closed in LAst 30 days] = "Closed 30 days",Footprint[SC])
4)SLA Final = IF(ISBLANK(Footprint[ALL Open]),Footprint[Days - Closed(30 days)],Footprint[ALL Open])
Output:
Please let me know if i can achieve this in a more better way.
Thanks,
Pinky
- ChandeepChhabra8 years ago
Impactful Individual
Hi Pinky0404,
Looks like you have created a lot of calculated columns. Found a bracket is missing in one of your measures
2)Closed in LAst 30 days = IF((Footprint[Date Closed]> (Footprint[RD]-30)) && (Footprint[Date Closed]<=Footprint[RD]),"Closed 30 days","Null")
Can you share your pbix file, I'll be able to write a measure that does the same