Forum Discussion
Calculate Service for Distinct Techs
- 5 years ago
ConnieMaldonado , You can have measure like this
sumx(summarize(Table, Table[Tech Name],[Tech Hire Date]), datediff([Tech Hire Date], today(),DAY)/30)
You can have
Averagex(summarize(Table, Table[Tech Name],[Tech Hire Date]), datediff([Tech Hire Date], today(),DAY)/30)
or use min of hire date
sumx(summarize(Table, Table[Tech Name], "_TechHireDate",Min([Tech Hire Date])), datediff([_TechHireDate], today(),DAY)/30)
ConnieMaldonado , You can have measure like this
sumx(summarize(Table, Table[Tech Name],[Tech Hire Date]), datediff([Tech Hire Date], today(),DAY)/30)
You can have
Averagex(summarize(Table, Table[Tech Name],[Tech Hire Date]), datediff([Tech Hire Date], today(),DAY)/30)
or use min of hire date
sumx(summarize(Table, Table[Tech Name], "_TechHireDate",Min([Tech Hire Date])), datediff([_TechHireDate], today(),DAY)/30)
Awesome! Thank you.