Forum Discussion
Calculate Date and Time difference considering the weekends and workhours
- 9 years ago
The only possibility I can think of is that there is something wrong with the Calendar'[WorkDay] formula. Could you please check this column formula is like below? The data type of this column should be “True/False”.
If it is actually same as mine, could you please upload your .pbix file to OneDrive and share it with me? In that case I can take a look at your .pbix file and try to solve the problem.
Best Regards,
Herbert
- 9 years ago
How about the result if we update the “FirstDaySecDiff” measure as below?
FirstDaySecDiff = IF ( Table1[FirstDayEndTime] >= Table1[DateTimeFrom] && Table1[FirstDayEndTime] <= Table1[DateTimeTo], DATEDIFF ( Table1[DateTimeFrom], Table1[FirstDayEndTime], SECOND ), IF ( Table1[FirstDayEndTime] >= Table1[DateTimeFrom] && Table1[FirstDayEndTime] > Table1[DateTimeTo], DATEDIFF ( Table1[DateTimeFrom], Table1[DateTimeTo], SECOND ), 0 ) )Best Regards,
Herbert
There may be several methods to get the expected result. I’ll divide the difference to three parts, the first day, the middle days and the last day. For details, please refer to following steps.
I’ve also upload my .pbix file here for reference.
- Create a calendar table with following formula. But do not create relationship between these two tables.
Calendar = CALENDAR ( "1/1/2016", "12/31/2016" )
- Create a column in calendar table to mark the working days.
WorkDay = VAR WeekDayNum = WEEKDAY ( 'Calendar'[Date], 2 ) RETURN ( IF ( WeekDayNum = 6 || WeekDayNum = 7, FALSE (), TRUE () ) ) - Create a column to store the working end time of first day.
FirstDayEndTime = DATE ( YEAR ( Table1[DateTimeFrom] ), MONTH ( Table1[DateTimeFrom] ), DAY ( Table1[DateTimeFrom] ) ) & " 18:00:00"
- Create a column to calculate the working seconds of first day.
FirstDaySecDiff = DATEDIFF ( Table1[DateTimeFrom], Table1[FirstDayEndTime], SECOND )
- Create a column to store the working start time of last day.
LastDayStartTime = DATE ( YEAR ( Table1[DateTimeTo] ), MONTH ( Table1[DateTimeTo] ), DAY ( Table1[DateTimeTo] ) ) & " 8:00:00"
- Create a column to store the working end time of last day.
LastDayEndTime = DATE ( YEAR ( Table1[DateTimeTo] ), MONTH ( Table1[DateTimeTo] ), DAY ( Table1[DateTimeTo] ) ) & " 18:00:00"
- Create a column to calculate the working seconds of last day.
LastDaySecDiff = IF ( FORMAT ( Table1[DateTimeFrom], "Short Date" ) <> FORMAT ( Table1[DateTimeTo], "Short Date" ), IF ( Table1[DateTimeTo] >= Table1[LastDayStartTime] && Table1[DateTimeTo] <= Table1[LastDayEndTime], DATEDIFF ( Table1[LastDayStartTime], Table1[DateTimeTo], SECOND ), IF ( Table1[DateTimeTo] > Table1[LastDayEndTime], DATEDIFF ( Table1[LastDayStartTime], Table1[LastDayEndTime], SECOND ), 0 ) ), 0 ) - Create a column to calculate the working seconds of middle days.
MidDaysSecDiff = IF ( FORMAT ( Table1[DateTimeFrom], "Short Date" ) <> FORMAT ( Table1[DateTimeTo], "Short Date" ), 3600 * 10 * ( CALCULATE ( DISTINCTCOUNT ( 'Calendar'[Date] ), FILTER ( 'Calendar', 'Calendar'[Date] > Table1[FirstDayEndTime] && 'Calendar'[Date] < Table1[LastDayStartTime] && 'Calendar'[WorkDay] = TRUE () ) ) - 1 ), 0 ) - Create the final column to calculate the total working hours.
TotalHourDiff = ( Table1[FirstDaySecDiff] + Table1[LastDaySecDiff] + Table1[MidDaysSecDiff] ) / 3600
Note: The data type of columns of “FirstDayEndTime”, “LastDayStartTime” and “LastDayEndTime” should be Date/Time as below.
Best Regards,
Herbert
Herbert,
Thank you so much for your help.
But unfortunately DATEDIFF gives an error "In DATEDIFF function, the start date cannot be greater than the end date"
because some hours on "DateTimeFrom" are greater than the "FirstDayEndTime" as you can see on the picture
I tried to fix this, but I couldn't do it.
Thank you!
- v-haibl-msft10 years agoMicrosoft Employee
Please update the DAX formula of FirstDaySecDiff column as below and have a try again.
FirstDaySecDiff = IF ( Table1[FirstDayEndTime] >= Table1[DateTimeFrom], DATEDIFF ( Table1[DateTimeFrom], Table1[FirstDayEndTime], SECOND ), 0 )Best Regards,
Herbert
- dcs13610 years agoAdvocate I
Herbert,
Thanks again for your help and sorry for bothering you again,
The last problem was solved, but I still have a problem with the MidDaysSecDiff column.
As you can see on the screen below, It gives an erro saying that DAX can't compare date values with True/False values.
- v-haibl-msft9 years agoMicrosoft Employee
It seems there are extra expression in your formula screenshot as below. How about the result if you remove it?
If problem persits, could you please give a complete screenshot for this MidDaysSecDiff formula?
Best Regards,
Herbert
- nadirS5 years agoHelper I
is there a way i can do a reversal on the same thing that you explained above - I have a date table and i am able to calculate working days.(0s for weekends and 1's for Weekdays). I need to add 5 days to my start date and and pick the appropriate working date from the date table so that it gives me an "Expected Completion Date" that takes account of weekends.