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minapot's avatar
minapot
Frequent Visitor
8 years ago
Solved

Avg Hrs Worked

Hi! Need help please on the following calculation that I need to translate to PBI. Here's what I got in Excel.                                   I need to be able to compute f...
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  • danextian's avatar
    danextian
    8 years ago

    Hi minapot,

     

    Try this:

     

    Avg =
IF (
    HASONEVALUE ( table[emp_id] ),
    DIVIDE ( SUM ( table[total hrs worked] ), COUNT ( table[wknum] ) ),
    DIVIDE (
        DIVIDE ( COUNT ( table[wknum] ), [measure to divide] ),
        DISTINCTCOUNT ( table[emp_id] )
    )
)

    Replace the text in red with the appropriate measure since you did not mention which column to divide the count of weeks by for the average. 

Floriankx's avatar
Floriankx
Solution Sage
8 years ago

Hello,

 

after loading your data to DataModel you can create the following measures:

CountOfWeeks=Count(Table[wknum])
Total_hrs=Sum(Table[total hrs worked])
avg_hrs=[Total_hrs]/[CountOfWeeks]

 

Best regards.

minapot's avatar
minapot
Frequent Visitor
8 years ago

Hi Floriankx! Thanks for your reply! I tried your suggestions but failed to get the correct output.

For the overall avg hrs worked, I need to have the total worked hrs for the site/account and then divide that by the average number of weeks the employees for that site/account worked and then divide the answer to the distinct # of employees for that site/account.

 

so... site/account avg hrs worked = (total hours worked per site/ave # of weeks with schedule)/distinctcount(HC)

  • danextian's avatar
    danextian
    Super User
    8 years ago

    Hi minapot,

     

    Try this:

     

    Avg =
IF (
    HASONEVALUE ( table[emp_id] ),
    DIVIDE ( SUM ( table[total hrs worked] ), COUNT ( table[wknum] ) ),
    DIVIDE (
        DIVIDE ( COUNT ( table[wknum] ), [measure to divide] ),
        DISTINCTCOUNT ( table[emp_id] )
    )
)

    Replace the text in red with the appropriate measure since you did not mention which column to divide the count of weeks by for the average.