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fabd's avatar
fabd
Icon for Helper I rankHelper I
4 years ago
Solved

Average day for incident resolution

Hi, I haven't practice for several years.. I must admit that i lost everything, and i am unable to do what i need.   So, what i want ?   My boss give me a new responsability : KPI for my team ! ...
  • v-kkf-msft's avatar
    4 years ago

    Hi fabd ,

     

    Please create the new column:

     

    Duree = 
    DATEDIFF (
        incident_STI_indus[date_creation],
        incident_STI_indus[date_fermeture],
        MINUTE
    )

     

    Then create the measure:

     

    Measure = 
    VAR AveDur =
        AVERAGE ( incident_STI_indus[Duree] )
    VAR Days =
        INT ( AveDur / 60 / 24 )
    VAR Hours =
        INT ( AveDur / 60 - Days * 24 )
    VAR Minutes =
        ROUND ( MOD ( AveDur, 60 ), 0 )
    VAR DaysText =
        IF ( Days >= 1, FORMAT ( Days, "General Number" ) & " days" )
    VAR HoursText =
        FORMAT ( Hours, "General Number" ) & " hours"
    VAR MinutesText =
        FORMAT ( Minutes, "General Number" ) & " min"
    RETURN
        COMBINEVALUES ( ", ", DaysText, HoursText, MinutesText )

     

    If the problem is still not resolved, please provide detailed error information or the expected result you expect. Let me know immediately, looking forward to your reply.
    Best Regards,
    Winniz
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.