Forum Discussion
sdas028
8 years agoHelper I
Average Head Count by Week
Hi, I am trying to calculate average head count by ISOWEEK. I have a data table that contains employee number, employee name, date of shift, position, isoweek. As the data has an inidvidual line for ...
- 8 years ago
Hi sdas028,
You should use the following formula and check if it works fine.average=COUNTROWS(Table)/DISTINCTCOUNT(Table[Emplyeename])
Best Regards,
Angelia
sdas028
8 years agoHelper I
Hi
Here is a sample lot of the data I have, there is employee name and position as well but didnt want to include that information
| Employee Number | Hours Worked | Date | Isoweek |
| 50172 | 5 | 30/04/2018 | 18 |
| 50437 | 3.75 | 30/04/2018 | 18 |
| 50711 | 3.75 | 30/04/2018 | 18 |
| 50055 | 10.25 | 1/05/2018 | 18 |
| 50437 | 11.25 | 1/05/2018 | 18 |
| 50711 | 11.25 | 1/05/2018 | 18 |
| 51124 | 11.5 | 1/05/2018 | 18 |
| 50055 | 11 | 2/05/2018 | 18 |
| 50172 | 12.75 | 2/05/2018 | 18 |
| 50437 | 11.5 | 2/05/2018 | 18 |
| 50711 | 11.75 | 2/05/2018 | 18 |
| 51124 | 11.75 | 2/05/2018 | 18 |
| 50055 | 7.5 | 3/05/2018 | 18 |
| 50172 | 13.25 | 3/05/2018 | 18 |
| 50437 | 13.25 | 3/05/2018 | 18 |
| 50711 | 11.25 | 3/05/2018 | 18 |
| 51124 | 14 | 3/05/2018 | 18 |
| 50055 | 9 | 4/05/2018 | 18 |
| 50172 | 11 | 4/05/2018 | 18 |
| 50437 | 9.75 | 4/05/2018 | 18 |
| 51124 | 10.25 | 4/05/2018 | 18 |
| 50055 | 10 | 5/05/2018 | 18 |
| 50172 | 11.75 | 5/05/2018 | 18 |
| 50711 | 10.75 | 5/05/2018 | 18 |
| 51124 | 6.75 | 5/05/2018 | 18 |
| 50055 | 8.5 | 6/05/2018 | 18 |
| 50172 | 11.25 | 6/05/2018 | 18 |
| 50437 | 10.5 | 6/05/2018 | 18 |
| 50711 | 10.5 | 6/05/2018 | 18 |
| 50172 | 12 | 7/05/2018 | 19 |
| 50437 | 10.25 | 7/05/2018 | 19 |
| 50711 | 12.5 | 7/05/2018 | 19 |
| 50055 | 8.75 | 8/05/2018 | 19 |
| 50437 | 8 | 8/05/2018 | 19 |
| 50711 | 9 | 8/05/2018 | 19 |
| 51124 | 7 | 8/05/2018 | 19 |
| 50055 | 11.5 | 9/05/2018 | 19 |
| 50172 | 12.5 | 9/05/2018 | 19 |
| 50437 | 11.25 | 9/05/2018 | 19 |
| 50711 | 13 | 9/05/2018 | 19 |
| 51124 | 11 | 9/05/2018 | 19 |
| 50055 | 7.5 | 10/05/2018 | 19 |
| 50172 | 10.25 | 10/05/2018 | 19 |
| 50437 | 9.5 | 10/05/2018 | 19 |
| 50711 | 11 | 10/05/2018 | 19 |
| 50055 | 7.5 | 11/05/2018 | 19 |
| 50172 | 10.25 | 11/05/2018 | 19 |
| 50437 | 9.75 | 11/05/2018 | 19 |
| 51124 | 9 | 11/05/2018 | 19 |
| 50055 | 8.75 | 12/05/2018 | 19 |
| 50172 | 9 | 12/05/2018 | 19 |
| 50711 | 5.25 | 12/05/2018 | 19 |
| 51124 | 4 | 12/05/2018 | 19 |
| 50437 | 10 | 14/05/2018 | 20 |
| 50172 | 7.75 | 15/05/2018 | 20 |
| 50437 | 8.25 | 15/05/2018 | 20 |
| 50711 | 8.75 | 15/05/2018 | 20 |
| 50172 | 9.75 | 16/05/2018 | 20 |
| 50437 | 10 | 16/05/2018 | 20 |
| 50711 | 9.75 | 16/05/2018 | 20 |
| 50055 | 7.5 | 17/05/2018 | 20 |
| 50172 | 8.5 | 17/05/2018 | 20 |
| 50437 | 8.5 | 17/05/2018 | 20 |
| 50711 | 9 | 17/05/2018 | 20 |
| 50055 | 7.5 | 18/05/2018 | 20 |
| 50437 | 10.25 | 18/05/2018 | 20 |
| 50055 | 9.25 | 19/05/2018 | 20 |
| 50172 | 9.5 | 19/05/2018 | 20 |
| 50711 | 10 | 19/05/2018 | 20 |
| 50055 | 7 | 20/05/2018 | 20 |
| 50172 | 9 | 20/05/2018 | 20 |
| 50437 | 8.75 | 20/05/2018 | 20 |
| 50711 | 9.25 | 20/05/2018 | 20 |
| 50172 | 10.75 | 21/05/2018 | 21 |
| 50711 | 10.75 | 21/05/2018 | 21 |
| 50055 | 7.5 | 22/05/2018 | 21 |
| 50437 | 12 | 22/05/2018 | 21 |
| 50711 | 10.75 | 22/05/2018 | 21 |
| 50055 | 1.75 | 23/05/2018 | 21 |
| 50172 | 3 | 23/05/2018 | 21 |
| 50437 | 2 | 23/05/2018 | 21 |
| 50711 | 2.25 | 23/05/2018 | 21 |
| 50172 | 8.5 | 24/05/2018 | 21 |
| 50437 | 7.75 | 24/05/2018 | 21 |
| 50711 | 7.5 | 24/05/2018 | 21 |
| 50437 | 6.5 | 25/05/2018 | 21 |
| 50055 | 9.5 | 26/05/2018 | 21 |
| 50172 | 10.5 | 26/05/2018 | 21 |
| 50711 | 9.75 | 26/05/2018 | 21 |
| 50055 | 13.25 | 27/05/2018 | 21 |
| 50172 | 13.25 | 27/05/2018 | 21 |
| 50437 | 12 | 27/05/2018 | 21 |
| 50711 | 6.5 | 27/05/2018 | 21 |
erikajain02
8 years agoResolver I
Is this what is required as output ?
- sdas0288 years agoHelper I
I have managed to also get to this table - however I would have thought that the average for week 21 should be 5? 20 shifts in one week worked by 4 people should give an average of 5, or perhaps I am incorrect in my thinking and possibly overthinking the calculation
- Seward125338 years agoSolution SageIs week 21 a complete or partial week?
- sdas0288 years agoHelper I
Do you mean did they work a full week?