Forum Discussion
Fabric Pyspark Help. Adding a Min into a group by agg code in Notebooks
It would be really useful if we had a Pyspark forum
Im SQL through and through and learning Pyspark is a NIGHTMARE
I have the following code that finds all the contestants with more that one record in a list that should be unique
- Anonymous2 years ago
Hi DebbieE ,
Thanks for using Fabric Community.
As I understand -
Spark SQL Code:df = spark.sql("SELECT Min(CustomerID), CompanyName, Count(*) FROM gopi_lake_house.customer_table1 group by CompanyName having count(*)>1") display(df)
Pyspark Code:
Can you please try below code -from pyspark.sql.functions import * result = dfcont.groupBy('CompanyName')\ .agg(min('CustomerID').alias('minCustomerID'), count('CustomerID').alias('TotalRecords'))\ .filter(col('TotalRecords') > 1)\ .show(1000)
Hope this is helpful. Please let me know incase of further queries.
3 Replies
- AnonymousNot applicable
Hi DebbieE ,
Thanks for using Fabric Community.
As I understand -
Spark SQL Code:df = spark.sql("SELECT Min(CustomerID), CompanyName, Count(*) FROM gopi_lake_house.customer_table1 group by CompanyName having count(*)>1") display(df)
Pyspark Code:
Can you please try below code -from pyspark.sql.functions import * result = dfcont.groupBy('CompanyName')\ .agg(min('CustomerID').alias('minCustomerID'), count('CustomerID').alias('TotalRecords'))\ .filter(col('TotalRecords') > 1)\ .show(1000)
Hope this is helpful. Please let me know incase of further queries. - DebbieECommunity Champion
Yey. It worked. thank you so much. the excercise is to try to do everything I usually do with pyspark so having these extra examples are gold too.
- AnonymousNot applicable
Hi DebbieE ,
Glad to know that your query got resolved. Please continue using Fabric Community on your further queries.