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Pan_Forex's avatar
Pan_Forex
Helper III
3 years ago
Solved

linear progression

Hello guys, do you have any idea how to easily add a fixed increment? The only thing I can think of is the if function, but I have several thousand rows and would prefer to streamline it 🙂 Simple da...
  • FreemanZ's avatar
    FreemanZ
    3 years ago

    hi Pan_Forex 

    then try this:

    y = 1- TRUNC( [x]/1000)*0.01

     

    please consider @ someone, if you seek further suggestions.

FreemanZ's avatar
FreemanZ
Super User
3 years ago

hi Pan_Forex 

from 4787 to 6222, from 8855 to 9001, why subtract 0.01 twice? 

Pan_Forex's avatar
Pan_Forex
Helper III
3 years ago

Because the range is between 0-1000, 1001-2000, in the second example there is an error. let's make it simple. For numbers < 1000-1, between 1001-2000=0,99, between 2001-3000=0,98 and so on

  • FreemanZ's avatar
    FreemanZ
    Super User
    3 years ago

    hi Pan_Forex 

    then try this:

    y = 1- TRUNC( [x]/1000)*0.01

     

    please consider @ someone, if you seek further suggestions.