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Anonymous
Not applicable

calculate value and drop duplicates in groups

Here is the data and I want to drop duplicate in "name" level by get the max value,

null_0-1664351670562.png

 

for example, after drop duplicates in name level, the sum value of type "high" is 2+5 rather than 2+2+5+4

do you have any ideas? Thank you.

 

1 ACCEPTED SOLUTION

Hi,

thank you for your feedback, and please check the below picture and the attached pbix file whether it suits your requirement.

 

Jihwan_Kim_0-1664370338607.png

 

 

Expected outcome measure: =
SUMX (
    SUMMARIZE ( Data, Data[Type], Data[Category] ),
    CALCULATE ( MAX ( Data[Value] ) )
)

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


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Schedule a meeting with me to discuss further by clicking here.

View solution in original post

3 REPLIES 3
Jihwan_Kim
Super User
Super User

Hi,

I am not sure if I understood your question correctly, but please check the below picture and the attached pbix file.

It is for creating a new table.

 

Jihwan_Kim_0-1664367798856.png

 

New table create =
GROUPBY (
    Data,
    Data[Type],
    Data[Category],
    "@MaxValue", MAXX ( CURRENTGROUP (), Data[Value] )
)

 

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Visit my LinkedIn page by clicking here.


Schedule a meeting with me to discuss further by clicking here.

Anonymous
Not applicable

actually I am finding a way to create a measure that calculate the sum of the max value in category group,

the result is exactly like this,

null_0-1664368426091.png

is there a way to change the table into a measure? Thank you.

 

Hi,

thank you for your feedback, and please check the below picture and the attached pbix file whether it suits your requirement.

 

Jihwan_Kim_0-1664370338607.png

 

 

Expected outcome measure: =
SUMX (
    SUMMARIZE ( Data, Data[Type], Data[Category] ),
    CALCULATE ( MAX ( Data[Value] ) )
)

If this post helps, then please consider accepting it as the solution to help other members find it faster, and give a big thumbs up.


Visit my LinkedIn page by clicking here.


Schedule a meeting with me to discuss further by clicking here.

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