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Frequent Visitor

## aggregate series

Hello,
I want to aggregate series, I am attaching a picture of my idea, does anyone have an existing solution?

1 ACCEPTED SOLUTION
Community Support

Hi, @borniex

You can try the following methods.

Column:

``````previous part = CALCULATE(MAX('Table'[part]),FILTER('Table',[id]=EARLIER('Table'[id])-1))
``````
``judgement = IF([part]=[previous part],1,0)//Determine if the part is the same as the previous id``
``First part = IF([judgement]=0,1,0)``
``Max ID = CALCULATE(Max('Table'[id]),FILTER('Table',[id]<=EARLIER('Table'[id])&&[First part]=1))``
``Sum value = CALCULATE(SUM('Table'[value]),ALLEXCEPT('Table','Table'[Max ID]))``

Is this the result you expect?

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

3 REPLIES 3
Community Support

Hi, @borniex

You can try the following methods.

Column:

``````previous part = CALCULATE(MAX('Table'[part]),FILTER('Table',[id]=EARLIER('Table'[id])-1))
``````
``judgement = IF([part]=[previous part],1,0)//Determine if the part is the same as the previous id``
``First part = IF([judgement]=0,1,0)``
``Max ID = CALCULATE(Max('Table'[id]),FILTER('Table',[id]<=EARLIER('Table'[id])&&[First part]=1))``
``Sum value = CALCULATE(SUM('Table'[value]),ALLEXCEPT('Table','Table'[Max ID]))``

Is this the result you expect?

Best Regards,

Community Support Team _Charlotte

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Frequent Visitor

Thank you very much, I was interested in this solution! Elegant, I thought more complicated 😄

Helper II

Hi.

You will need to read about the windows function (https://www.sqlbi.com/articles/introducing-window-functions-in-dax). I have never used it, but I understand that it can deal with you scenario.

Greg Oliveira

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