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Anonymous
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Unique Person based on accounts.
12-19-2022
09:51 PM
Hi All,
With a measure how do you find Unique person beind every team Number. For Example Account name A has 2 people but Person will be counted as 1 and other example be Josh1 has serval account name with single person the count will be 1. Result as shown in Result table.
Table1 | |
Person | Account Name |
Jake | A |
Jhon | A |
Joy | B |
Roy | C |
Tim | D |
Tina | E |
Josh | F |
Ryan | F |
Josh1 | Z |
Josh1 | Y |
Josh1 | X |
Josh1 | U |
Josh1 | W |
Result
Result | Account Name |
Jake, Jhon | 1 |
Joy | 1 |
Roy | 1 |
Tim | 1 |
Tina | 1 |
Josh | 1 |
Ryan | |
Josh1 | 1 |
Solved! Go to Solution.
1 ACCEPTED SOLUTION
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12-20-2022
10:08 PM
Hi @Anonymous ,
You can create a calculated column as below to get it:
Result =
CONCATENATEX (
FILTER ( 'Table1', 'Table1'[Account Name] = EARLIER ( 'Table1'[Account Name] ) ),
Table1[Person],
","
)
Best Regards
Community Support Team _ Rena
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
1 REPLY 1
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12-20-2022
10:08 PM
Hi @Anonymous ,
You can create a calculated column as below to get it:
Result =
CONCATENATEX (
FILTER ( 'Table1', 'Table1'[Account Name] = EARLIER ( 'Table1'[Account Name] ) ),
Table1[Person],
","
)
Best Regards
Community Support Team _ Rena
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

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