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raj777karthik's avatar
raj777karthik
Microsoft Employee
3 years ago
Solved

TOPN dax function as variable

Need to show top 5 services in table visual.   Service Name Count Total Count Apple 43 346 Samsumg 67 346 mi 80 346 oppo 84 346 google 72 346   Measure written we...
Table Column
raj777karthik's avatar
raj777karthik
Microsoft Employee
3 years ago

Hi,

Thanks for this approach,but we need to do this in existing table considering relationship.If i create table function then only few slicer interacting and not all.

  • v-yadongf-msft's avatar
    v-yadongf-msft
    Community Support
    3 years ago

    Hi raj777karthik ,

     

    If you don't want to create a new table, pleaser try following DAX to sort [Thread_] column:

     

    Rank = RANKX('Stack Tags','Stack Tags'[Thread__],'Stack Tags'[Thread__],DESC)

     

     

    Calculate the sum of the top 5:

     

    Total count = CALCULATE(SUM('Stack Tags'[Thread__]),FILTER(ALL('Stack Tags'),'Stack Tags'[Rank]<=5))

     

     

    Add the [Rank] column to Filters to filter out the top5: 

     

    Best regards,

    Yadong Fang

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

    • raj777karthik's avatar
      raj777karthik
      Microsoft Employee
      3 years ago

      In this since my service oppo has 84 count the rank is taking all these for 1 and second service mi  has 80 count ,rank is taken as 85 .And for third its taking as rank 165.

      • v-yadongf-msft's avatar
        v-yadongf-msft
        Community Support
        3 years ago

        Hi raj777karthik ,

         

        Please try following DAX to create three measures:

        Count = COUNT('Stack Tags'[Service]) 

Rank = RANKX(ALLSELECTED('Stack Tags'),[Count],,DESC,Dense)

Total count = CALCULATE([Count],FILTER(ALL('Stack Tags'),'Stack Tags'[Rank]<=5))

        You will get result you want:

        Best regards,

        Yadong Fang

        If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.