Forum Discussion
Valentin09
1 year agoRegular Visitor
Subtract two values based on Rank
I have the following table: I want to subtract the current testscore (Testrang = 1) with the previous testscore (Testrang = 2). In this example I want to have the following calculation: Nam...
- 1 year ago
Ok so in that case the visual must already have been filtered to the test type. If you have multiple tests per person, within the same type, how are you filtering it to show the 2 most recent results? If you are not filtering it, and you are using measures to display columns 2 & 3 of your visual, you'll need to factor this into the DAX, I suggest something like this:
VAR _name = SELECTEDVALUE ( 'Table'[Name] ) VAR _test_type = SELECTEDVALUE( 'Table'[Test] ) VAR _recent_test = MAX ( 'Table'[Testrang] ) VAR _recent_test_score = CALCULATE ( SUM ( 'Table'[Wert] ), REMOVEFILTERS ( 'Table'[Testrang] ), 'Table'[Testrang] = _recent_test && 'Table'[Name] = _name && 'Table'[Test] = _test_type ) VAR _prev_test = _recent_test - 1 VAR _prev_test_score = CALCULATE ( SUM ( 'Table'[Wert] ), REMOVEFILTERS ( 'Table'[Testrang] ), 'Table'[Testrang] = _prev_test && 'Table'[Name] = _name && 'Table'[Test] = _test_type ) VAR _current_minus_prev = _recent_test_score - _prev_test_score RETURN _current_minus_prevIf this works for you please accept as the solution for visibilty of others.
Anonymous
1 year agoNot applicable
Thanks for the replies from mark_endicott.
Hi Valentin09 ,
Based on your description, I created simple data:
Please try the following DAX formula:
Difference =
VAR _count=CALCULATE(COUNT('Table'[Name]),ALLEXCEPT('Table','Table'[Name]))
VAR _current=MAX('Table'[Testrang])
VAR CurrentTestrang=CALCULATE(SUM('Table'[Wert]),FILTER(ALLEXCEPT('Table','Table'[Name]),'Table'[Testrang]=_current))
VAR PreviousTestrang=CALCULATE(SUM('Table'[Wert]),FILTER(ALLEXCEPT('Table','Table'[Name]),'Table'[Testrang]=_current-1))
return
IF(_count>1&&_current>1,CurrentTestrang-PreviousTestrang,blank())
Result:
Best Regards,
Zhu
If there is any post helps, then please consider Accept it as the solution to help the other members find it more quickly.