Forum Discussion
Problem grouping by days
- Anonymous4 years ago
Hi Anonymous ,
I suggest you to add a date only column in your data table. It will help us to group the table in calculation.
Datevalue = DATEVALUE('Table'[Time])Try this code.
Measure = VAR _T = SUMMARIZE(ALL('Table'),'Table'[Datevalue],"Count",CALCULATE(DISTINCTCOUNT('Table'[Value]),ALLEXCEPT('Table','Table'[Datevalue])),"Max",CALCULATE(MAX('Table'[Value]),ALLEXCEPT('Table','Table'[Datevalue]))) RETURN COUNTAX(FILTER(_T,[Datevalue]<=MAX('Table'[Datevalue])&&[Count] = 1&&[Max] = 0),[Datevalue]) +0Result is as below.
Best Regards,
Rico ZhouIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Your sample data only covers one day, and it specifies a day that doesn't exist. Please provide better sample data that fully covers your issue.
- Anonymous4 years agoNot applicable
This is a more complete data. Basically I have a lot of locations and I would like to see how many consecutive days do I have with 0 data for a whole day in all locations
Time Location Value 01/01/2022 00:00 1 0.455741 01/01/2022 06:00 1 0 01/01/2022 12:00 1 0 01/01/2022 18:00 1 1 02/01/2022 00:00 1 0 02/01/2022 06:00 1 0 02/01/2022 12:00 1 0 02/01/2022 18:00 1 0 03/01/2022 00:00 1 0 03/01/2022 06:00 1 0 03/01/2022 12:00 1 0 03/01/2022 18:00 1 0 01/01/2022 00:00 2 0.433114 01/01/2022 06:00 2 0.778561 01/01/2022 12:00 2 0.961754 01/01/2022 18:00 2 0.878894 02/01/2022 00:00 2 0 02/01/2022 06:00 2 0 02/01/2022 12:00 2 0 02/01/2022 18:00 2 0 03/01/2022 00:00 2 0 03/01/2022 06:00 2 0 03/01/2022 12:00 2 0 03/01/2022 18:00 2 0 The output I am loo king for is a measure with the consecutive 0 values as below:
Date Measure 01/01/2022 0 02/01/2022 1 03/01/2022 2 - Anonymous4 years agoNot applicable
Hi Anonymous ,
I suggest you to add a date only column in your data table. It will help us to group the table in calculation.
Datevalue = DATEVALUE('Table'[Time])Try this code.
Measure = VAR _T = SUMMARIZE(ALL('Table'),'Table'[Datevalue],"Count",CALCULATE(DISTINCTCOUNT('Table'[Value]),ALLEXCEPT('Table','Table'[Datevalue])),"Max",CALCULATE(MAX('Table'[Value]),ALLEXCEPT('Table','Table'[Datevalue]))) RETURN COUNTAX(FILTER(_T,[Datevalue]<=MAX('Table'[Datevalue])&&[Count] = 1&&[Max] = 0),[Datevalue]) +0Result is as below.
Best Regards,
Rico ZhouIf this post helps, then please consider Accept it as the solution to help the other members find it more quickly.