Forum Discussion
Need Help: How to get the Distinct Count value based on the multiple Slicer Filters selection
I Have multiple Slicer Filters for Different CEO Types. Now I need to get the distinct count for the CEOs based on the multiple CEO selection.
Ex:
CEO - A
CEO Minus 1 = A,B,C,D
CEO Minus 2 = B,E,F,G
CEO Minus 3 = E,F,H,I,J and so on...
If I select B from CEO Minus 1 and B,E,F from CEO Minus 2 and H from CEO Minus 3 I have to show the distinct count as 4 in the Card.
Thanks in advance
Sanjeev
[# CEO] = // This measure will also work if you CEO's // are in different tables instead of one, T. var CeoMinus1 = values( T[CEO minus 1]) var CeoMinus2 = values( T[CEO minus 2]) ... // means: add more of these if you need in the same fashion var DistinctCeos = SUMX( DISTINCT( union( CeoMinus1, CeoMinus2, ... // same as before... ) ), 1 ) return DistinctCeosThanks daXtreme for your valuable time in providing the solution.
3 Replies
- daXtreme
Solution Sage
[# CEO] = // This measure will also work if you CEO's // are in different tables instead of one, T. var CeoMinus1 = values( T[CEO minus 1]) var CeoMinus2 = values( T[CEO minus 2]) ... // means: add more of these if you need in the same fashion var DistinctCeos = SUMX( DISTINCT( union( CeoMinus1, CeoMinus2, ... // same as before... ) ), 1 ) return DistinctCeos- SanjeevKumarFrequent Visitor
Hello daXtreme
This time I have different requirements for the same data. After so many different trials I am posting my query again here. Can you please provide the solution?
We have the CEO hierarchy as below and showing all these CEO types as different slicers.
CEO->CEO Minus 1->CEO Minus 2->CEO Minus 3->CEO Minus 4->CEO Minus 5->CEO Minus 6->CEO Minus 7->CEO Minus 8->CEO Minus 9
If I selected the combination of the lower Hierarchy CEO type and upper Hierarchy CEO types, I should get only the distinct count for the lower Hierarchy CEO type.
Ex:
CEO - A
CEO Minus 1 = A,B,C,D
CEO Minus 2 = B,E,F,G
CEO Minus 3 = E,F,H,I,J and so on...
Suppose we have selected the combination of "A" from CEO, "A", "B" from CEO Minus 1 and "B", "E", "F" from CEO Minus 2. We should get the distinct count as 3 from CEO Minus 2 slicer.
Thanks in advance.Sanjeev
- SanjeevKumarFrequent Visitor
Thanks daXtreme for your valuable time in providing the solution.