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Anonymous's avatar
Anonymous
Not applicable
2 years ago
Solved

Measure for query using IN statement

Hello, I need to write a measure to do the following query.  SELECT count(*) FROM table 1 a WHERE a.code IN (select b.code from table 2 b where b.id = selectedvalue(table3[id])   Appreciate any...
Need Help
  • Anonymous's avatar
    Anonymous
    2 years ago

    Hi Anonymous 

     

    Have you solved your problem? If so, can you share your solution here and mark the correct answer as a standard answer to help other members find it faster? Thank you very much for your kind cooperation!

     

    Best Regards

    Zhengdong Xu
    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

Anonymous's avatar
Anonymous
Not applicable
2 years ago

Thanks for a quick respond! When tried your solution it took loong time and got a message "Couldn't load the data for this visual". Table1 has more than 10 mln records and I have filters for visuals on the page. May be I need to add filters to the measure also? If you can add to your solution for table1 source_id = 1 and service_id = 2 ? Many thanks! 

aduguid's avatar
aduguid
Memorable Member
2 years ago

I tried to refactor the DAX 

SelectedCount = 
VAR SelectedID = SELECTEDVALUE(Table3[id])
RETURN
    CALCULATE(
        COUNTROWS(Table1),
        FILTER(
            Table1,
            Table1[code] IN 
            CALCULATETABLE(
                VALUES(Table2[code]),
                Table2[id] = SelectedID
            )
        )
    )
  • Anonymous's avatar
    Anonymous
    Not applicable
    2 years ago

    Thanks! I tried refactor measure and got nothing unfortunately...

    • Anonymous's avatar
      Anonymous
      Not applicable
      2 years ago

      Hi Anonymous 

       

      Have you solved your problem? If so, can you share your solution here and mark the correct answer as a standard answer to help other members find it faster? Thank you very much for your kind cooperation!

       

      Best Regards

      Zhengdong Xu
      If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.