Forum Discussion
Help With Complex Standard Deviation
Hi @tailspin,
Measure 2 doesn't reference Measure 1, so seems you are proposing only Measure 2?
I've done some general reading on the Web on topics related, and seems a formula that does the following will work:
Square Rool of the squared sums of the STDV of each resource plan.
Square Root (STDV.P(Plan A^2)+STDV.P(Plan B^2)+etc...)
hi jmfillman
"Square Root of the squared sums of the STDV of each resource plan."
Used below measure to implement above statement.
Measure Used
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Based on what I have read on web
When calculating SD, you use mean in the SD formula.
When calculating Weighted SD, you need to use weighted mean instead of simple mean. I am unable to fully understand the formula which I read on web, that is where I am stuck.
Measure 2 doesn't reference Measure 1, so seems you are proposing only Measure 2?
Measure1 was just for testing. Measure2 gives you SD at item level, but it is not weighted SD.