Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
4 years ago
Solved

Grouping column

Hi! I need to create a formula, when I will use an existing table but with grouping, how can I do it?
  • tamerj1's avatar
    tamerj1
    4 years ago

    Anonymous 

    Please try this

    Total Scores =
SUMX (
    DISTINCT (
        SELECTCOLUMNS (
            CALCULATETABLE ( Table, ALLEXCEPT ( Table, Table[question] ) ),
            "@question", [question],
            "@score", [score]
        )
    ),
    [@score]
)
tamerj1's avatar
tamerj1
Community Champion
4 years ago

Anonymous 

Yes exactly

Anonymous's avatar
Anonymous
Not applicable
4 years ago

but it doesn't work, when I just put averagex

 

  • tamerj1's avatar
    tamerj1
    Community Champion
    4 years ago

    Can you explain further with example? Also please confirm you are creating a calculated column not a measure

  • Anonymous's avatar
    Anonymous
    Not applicable
    4 years ago

    I'm creating a measure, sorry that I haven't mentioned. For sum it worked, for average not

  • tamerj1's avatar
    tamerj1
    Community Champion
    4 years ago

    Anonymous 
    I don't know how your visual look like but you may try

     

    Average Scores =
AVERAGEX (
    DISTINCT (
        SELECTCOLUMNS (
            CALCULATETABLE ( ALL ( Table ), ALLEXCEPT ( Table, Table[question] ) ),
            "@question", [question],
            "@score", [score]
        )
    ),
    [@score]
)

     

  • Anonymous's avatar
    Anonymous
    Not applicable
    4 years ago

    ALL() takes a column, not a table

  • tamerj1's avatar
    tamerj1
    Community Champion
    4 years ago

    It take either. But please re- copy the code as the location of all was wrong