Forum Discussion
Displaying Numbers in Words
Hi,
I'm looking at the way of displaying numbers as words using DAX.
I have a basic sum DAX measure and I want the display to be shown in words so example would be if the total is 100 then I would like it to show " one hundred" if the total adds up to 10.5 then I want it to display "eleven".
Is there a way to display numbers from the measure like that?
Here is a more concise version that can also be easily extended to more digit triplets, since the lookup table will be the same for each of the triplets.
Spelt2 = var l = {("1","one","eleven","ten"),("2","two","twelve","twenty"),("3","three","thirteen","thirty"), ("4","four","fourteen","fourty"),("5","five","fifteen","fifty"),("6","six","sixteen","sixty"), ("7","seven","seventeen","seventy"),("8","eight","eighteen","eighty"),("9","nine","nineteen","ninety")} var t = "0" & format(ParameterNumber[ParameterNumber Value],"#") var s = right(t,1) var d = left(right(t,2),1) var h = left(right(t,3),1) var sd = if(d="1",concatenatex(filter(l,[Value1]=s),[Value3]),concatenatex(filter(l,[Value1]=s),[Value2])) var dd = if(d>"1" || d & s = "10",concatenatex(filter(l,[Value1]=d),[Value4]) & " ") var hd = if(h>"0",concatenatex(filter(l,[Value1]=h),[Value2]) & " hundred ") return hd & dd & sdHere's the version for up to six digits:
Spelt2 = var l = {("1","one","eleven","ten"),("2","two","twelve","twenty"),("3","three","thirteen","thirty"), ("4","four","fourteen","fourty"),("5","five","fifteen","fifty"),("6","six","sixteen","sixty"), ("7","seven","seventeen","seventy"),("8","eight","eighteen","eighty"),("9","nine","nineteen","ninety")} var t = "0" & format(ParameterNumber[ParameterNumber Value],"#") var s = right(t,1) var d = left(right(t,2),1) var h = left(right(t,3),1) var ss = if(d="1",concatenatex(filter(l,[Value1]=s),[Value3]),concatenatex(filter(l,[Value1]=s),[Value2])) var dd = if(d>"1" || d & s = "10",concatenatex(filter(l,[Value1]=d),[Value4]) & " ") var hd = if(h>"0",concatenatex(filter(l,[Value1]=h),[Value2]) & " hundred ") var s2 = left(right(t,4),1) var d2 = left(right(t,5),1) var h2 = left(right(t,6),1) var ss2 = if(d2="1",concatenatex(filter(l,[Value1]=s2),[Value3]),concatenatex(filter(l,[Value1]=s2),[Value2])) var dd2 = if(d2>"1" || d2 & s2 = "10",concatenatex(filter(l,[Value1]=d2),[Value4]) & " ") var hd2 = if(h2>"0",concatenatex(filter(l,[Value1]=h2),[Value2]) & " hundred ") return if(ss2>"",hd2 & dd2 & ss2 & " thousand ") & hd & dd & ssIn action:
24 Replies
- AnonymousNot applicable
Anonymous
Here's What I tried to implement this using a measure.
Currently this handles upto 9999.
EX = //Currently Handles Upto 9999 //Number to be converted into words. Replace this with SELECTEDVALUE or as desired. VAR Number = SELECTEDVALUE(T[Value])//115 VAR NumberToText = "" & Number VAR NoOfDigits = LEN ( NumberToText ) VAR Ones = SELECTCOLUMNS ( GENERATESERIES ( 0, 9, 1 ), "Ones Digit", [Value], "Ones Digit in Words", SWITCH ( [Value], 1, "One", 2, "Two", 3, "Three", 4, "Four", 5, "Five", 6, "Six", 7, "Seven", 8, "Eight", 9, "Nine" ) ) VAR OneTens = SELECTCOLUMNS ( GENERATESERIES ( 1, 9, 1 ), "One Tens Digit", [Value], "One Tens Words", SWITCH ( [Value], 1, "Eleven", 2, "Twelve", 3, "Thirteen", 4, "Fourteen", 5, "Fifteen", 6, "Sixteen", 7, "Seventeen", 8, "Eighteen", 9, "Nineteen" ) ) VAR Tens = SELECTCOLUMNS ( GENERATESERIES ( 1, 9, 1 ), "Tens Place", [Value], "Tens Words", SWITCH ( [Value], 1, "Ten", 2, "Twenty", 3, "Thirty", 4, "Fourty", 5, "Fifty", 6, "Sixty", 7, "Seventy", 8, "Eighty", 9, "Ninety" ) ) VAR PlaceValue = SELECTCOLUMNS ( GENERATESERIES ( 3, 6, 1 ), "Place", [Value], "Place Value", SWITCH ( [Value], 3, "Hundred", 4, "Thousand") ) VAR X = SELECTCOLUMNS ( GENERATESERIES ( 1, NoOfDigits, 1 ), "Index", [Value], "Dec", VAR N = INT ( Number / INT ( 1 & REPT ( "0", [Value] - 1 ) ) ) RETURN MOD ( N, 10 ) ) VAR numberMod100 = MOD(Number, 100) VAR Y = ADDCOLUMNS ( X, "Text", SWITCH ( TRUE (), [Index] = 1, SWITCH ( TRUE (), numberMod100 > 10 && numberMod100 < 20, MAXX ( FILTER ( OneTens, [One Tens Digit] = [Dec] ), [One Tens Words] ), MAXX ( FILTER ( Ones, [Ones Digit] = [Dec] ), [Ones Digit in Words] ) ), [Index] = 2, SWITCH ( TRUE (), numberMod100 > 10 && numberMod100 < 20, "", MAXX ( FILTER ( Tens, [Tens Place] = [Dec] ), [Tens Words] ) ), // Handles for 1-9 and beyond index 2 IF ( [Dec] = 0, "", // get the Word representation of current Digit MAXX ( FILTER ( Ones, [Ones Digit] = [Dec] ), [Ones Digit in Words] ) // Concatenate the current digit with its place value. & " " & MAXX ( FILTER ( PlaceValue, [Place] = [Index] ), [Place Value] ) ) ) ) RETURN CONCATENATEX(Y, [Text], " ", [Index], DESC)This can be extended to handle every natural number with few more lines of DAX.
Hope you get the idea.
Hope lbendlin can help on this. I don't know if there's a better way than this.
Thanks
- lbendlinSuper User
For simplified English you only need to solve for the last group of three digits, in a 1-2 pattern. Any other larger digit places are just repetition, with "thousand", "million" etc slapped on.
At least that's my theory...
- lbendlinSuper User
Here's my version for the last three digits. "ParameterNumber[ParameterNumber value]" is the measure that you want to convert. Nothing is returned for Zero.
Spelt = var t = "000" & format(ParameterNumber[ParameterNumber Value],"#") var s = right(t,1) var ss = switch(s,"1","one","2","two","3","three","4","four","5","five","6","six","7","seven","8","eight","9","nine","") var sd = right(t,2) var sds = switch(sd,"01","one","02","two","03","three","04","four","05","five","06","six","07","seven","08","eight","09","nine","10","ten" ,"11","eleven","12","twelve","13","thirteen","14","fourteen","15","fifteen","16","sixteen","17","seventeen" ,"18","eighteen","19","nineteen","") var t1 = left(t,len(t)-1) var d = right(t1,1) var ds = switch(d,"2","twen","3","thir","4","four","5","fif","6","six","7","seven","8","eigh","9","nine","") var dd = switch(d,"0","","1","",ds & "ty ") var t2 = left(t1,len(t1)-1) var h = right(t2,1) var hs = switch(h,"1","one","2","two","3","three","4","four","5","five","6","six","7","seven","8","eight","9","nine","") var hd = switch(h,"0","",hs & " hundred ") return hd & dd & if(d<"2",sds,ss)
- lbendlinSuper User
in which languages, and which dialects? Do you expect "two thousand one hundred fourty five" or "twenty one forty five" ? etc.
- AnonymousNot applicable
Hi,
I have been asked to produce something very similar, but also include the decimals as part of the text string. How would I be able to augment the dax measure code below to include the decimal values.i.e. £1001.99
converts to One Thousand and One Pounds and Ninety Nine Pence
- lbendlinSuper User
shouldn't that be "One Thousand One Pound and Ninety Nine Pence " ?
You will need to explain the (british) english rules a bit more.
- AnonymousNot applicable
Yes, that is correct typo on my part. I've listed out below a list of examples which follow the convention used in English I think you mean by rules. If the unit value is 1 we use the singular Pound, once pound value is greater than 1 we use the plural (Pounds). Anything to the right of the decimal point is always pence. If I've mis-interpreted your ask please let me know.
Some simple rules:
£0.99 = Ninety Nine Pence
£1.00 = One Pound
£1.99 = One Pound and Ninety Nine Pence
£10.00 = Ten Pounds
£100.00 = One Hundred Pounds
£101.00 = One Hundred and One Pounds
£110.00 = One Hundred and Ten Pounds£1000.00 = One Thousand Pounds
£1001.00 = One Thousand and One Pounds
£1,010.00 = One Thousand and Ten Pounds
£1,100.00 = One Thousand One Hundred Pounds
£10,000.00 = Ten Thousand Pounds
£10,001.00 = Ten Thousand and One Pounds
£10,010.00 = Ten Thousand and Ten Pounds
£10,100.00 = Ten Thousand One Hundred Pounds
£10,101.00 = Ten Thousand One Hundred and One Pounds
£10,110.00 = Ten Thousand One Hundred and Ten Pounds
£100,000.00 = One Hundred Thousand Pounds
£100,001.00 = One Hundred Thousand and One Pounds
£100,010.00 = One Hundred Thousand and Ten Pounds
£100,100.00 = One Hundred Thousand and One Hundred Pounds
£100,110.00 = One Hundred Thousand One Hundred and Ten Pounds
£101,000.00 = One Hundred and One Thousand Pounds
£101,001.00 = One Hundred and One Thousand and One Pounds
£101,010.00 = One Hundred and One Thousand and Ten Pounds
£101,110.00 = One Hundred and One Thousand One Hundred and Ten Pounds
£110,000.00 = One Hundred and Ten Thousand Pounds
£1,000,000.00 = One Million Pounds
£1,000,001.00 = One Million and One Pounds
£1,000,010.00 = One Million and Ten Pounds
£1,000,100.00 = One Million and One Hundred Pounds
£1,000,110.00 = One Million One Hundred and Ten Pounds
£1,001,110.00 = One Million One Thousand One Hundred and Ten Pounds
£1,010,110.00 = One Million Ten Thousand One Hundred and Ten Pounds
£1,110,110.00 = One Million One Hundred and Ten Thousand One Hundred and Ten Pounds
Regards
JAD22
- lbendlinSuper User
Attached to message 13