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Bergh
Helper II
Helper II

Date issue

Hi. I have a date column that takes away 9 days. [date] -9, but I would not like to include Saturday and Sunday. Only working days / weekdays.

1 ACCEPTED SOLUTION

ea_minus_9 =
VAR Period = 9
VAR EndDate = TableName[ea]
RETURN
    IF (
        NOT ISBLANK ( EndDate ),
        VAR StartDate = EndDate - 2 * Period
        VAR DatesPeriod =
            CALENDAR ( StartDate, EndDate )
        VAR DatesAndWDs =
            ADDCOLUMNS (
                DatesPeriod,
                "@WorkingDay",
                    VAR DayOfWeek =
                        WEEKDAY ( [Date], 2 )
                    RETURN
                        IF ( DayOfWeek IN { 6, 7 }, "No", "Yes" )
            )
        VAR WDsOnly =
            FILTER ( DatesAndWDs, [@WorkingDay] = "Yes" )
        VAR TopNTable =
            TOPN ( Period + 1, WDsOnly, [Date], DESC )
        RETURN
            MINX ( TopNTable, [Date] )
    )

View solution in original post

12 REPLIES 12
tamerj1
Super User
Super User

Hi @Bergh 
This one is tested and confirmed working both ways. If you want to add dates you use N if youi want to minus days you use -N

 

ea_plus/minus_9 = 
VAR Period = -9
VAR Date1 = 'Date'[Date]
RETURN
    IF (
        NOT ISBLANK ( Date1 ),
        VAR Date2 = Date1 + 2 * Period
        VAR DatesPeriod =
            CALENDAR ( MIN ( Date1, Date2 ), MAX ( Date1, Date2 ) )
        VAR DatesAndWDs =
            ADDCOLUMNS (
                DatesPeriod,
                "@WorkingDay",
                    VAR DayOfWeek =
                        WEEKDAY ( [Date], 2 )
                    RETURN
                        IF ( DayOfWeek IN { 6, 7 }, "No", "Yes" )
            )
        VAR WDsOnly =
            FILTER ( DatesAndWDs, [@WorkingDay] = "Yes" )
        RETURN
            IF ( 
                Date1 < Date2,
                    MAXX ( TOPN ( ABS ( Period ) + 1, WDsOnly, [Date], ASC ), [Date] ),
                    MINX ( TOPN ( ABS ( Period ) + 1, WDsOnly, [Date], DESC ), [Date] )
            )
    )

 

Yes, now it works thanks!!

Bergh
Helper II
Helper II

Hi again, so there is no easy way like in Excel with =workdays[date]-9 ??

The columns look like this. If we look at ea_minus_25 2006-11-29. That was a Wednesday, so I if I take -9 it will should be 2006-11-17 because there are 2 weekends. So If I do a Date Table how do I fix this??

EA-MINUSEA-MINUS

Hi @Bergh 
There is no easy way

you can use the following code without the need for the date table

ea_minus_9
VAR Period = 9
VAR EndDate = TableName[ea]
VAR StartDate = EndDate - 2 * Period
VAR DatesPeriod = CALENDAR ( StartDate, EndDate )
VAR DatesAndWDs = 
    ADDCOLUMNS ( 
        DatesPeriod,
        "@WorkingDay",
        VAR DayOfWeek = WEEKDAY( [Date], 2)
        RETURN
            IF ( DayOfWeek In { 6, 7 }, "No", "Yes" )
    )
VAR WDsOnly = FILTER ( DatesAndWDs, [@WorkingDay] = "Yes" )
VAR TopNTable = TOPN ( Period + 1, WDsOnly, [Date], DESC )
RETURN
    MINX ( TopNTable, [Date] )

I had some blank cells, then iI get a error. How do I do to fix this??

ea_minus_9 =
VAR Period = 9
VAR EndDate = TableName[ea]
RETURN
    IF (
        NOT ISBLANK ( EndDate ),
        VAR StartDate = EndDate - 2 * Period
        VAR DatesPeriod =
            CALENDAR ( StartDate, EndDate )
        VAR DatesAndWDs =
            ADDCOLUMNS (
                DatesPeriod,
                "@WorkingDay",
                    VAR DayOfWeek =
                        WEEKDAY ( [Date], 2 )
                    RETURN
                        IF ( DayOfWeek IN { 6, 7 }, "No", "Yes" )
            )
        VAR WDsOnly =
            FILTER ( DatesAndWDs, [@WorkingDay] = "Yes" )
        VAR TopNTable =
            TOPN ( Period + 1, WDsOnly, [Date], DESC )
        RETURN
            MINX ( TopNTable, [Date] )
    )

If I want to Period = -6 Can I do that??

@Bergh 
Not tested but I guess this should work both ways

ea_minus_9 =
VAR Period = 9
VAR Date1 = TableName[ea]
RETURN
    IF (
        NOT ISBLANK ( EndDate ),
        VAR Date2 = Date1 - 2 * Period
        VAR DatesPeriod =
            CALENDAR ( MAX ( Date1, Date2 ), MAX ( Date1, Date2 ) )
        VAR DatesAndWDs =
            ADDCOLUMNS (
                DatesPeriod,
                "@WorkingDay",
                    VAR DayOfWeek =
                        WEEKDAY ( [Date], 2 )
                    RETURN
                        IF ( DayOfWeek IN { 6, 7 }, "No", "Yes" )
            )
        VAR WDsOnly =
            FILTER ( DatesAndWDs, [@WorkingDay] = "Yes" )
        RETURN
            IF (
                Date1 > Date2,
                MINX ( TOPN ( Period + 1, WDsOnly, [Date], DESC ), [Date] ),
                MINX ( TOPN ( Period - 1, WDsOnly, [Date], ASC ), [Date] )
            )
    )

No nothing happens. It is the same date 2022-05-20 become 2022-05-20

Thanks! It works perfect!!

 

tamerj1
Super User
Super User

Hi @Bergh 
Not sure if your talking about a date table. However if you dont have a weekday column you can create one or just store in a variable

Working Day = 
VAR DayOfWeek = WEEKDAY( 'Date'[Date], 2)
RETURN
IF ( DayOfWeek In { 6, 7 }, "No", "Yes" )

You can then use this calculated column to filter your data

9 Days Ago = 
MINX (
    TOPN ( 
        9,
        FILTER ( 'Date', 'Date'[Date] < EARLIER ( 'Date'[Date] ) && 'Date'[Working Day] = "Yes" ),
        'Date'[Date],
        DESC
    ),
    'Date'[Date]
)

 

ValtteriN
Super User
Super User

Hi,

One way to do this is to add the following column in your calendar table:

Working days before today = IF(and(and(WEEKDAY('Calendar'[Date],2)<>6,WEEKDAY('Calendar'[Date],2)<>7),[date]<=TODAY()),1,0)

Then simply use these as a filter:

ValtteriN_0-1653029744252.png


I hope this post helps to solve your issue and if it does consider accepting it as a solution and giving the post a thumbs up!

My LinkedIn: https://www.linkedin.com/in/n%C3%A4ttiahov-00001/





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