Forum Discussion
wyanjaspew
Advocate I
3 years agoDISTINCTCOUNT
Hi Everyone, Please help me on this. TA
- 3 years ago
oh got it, doesn't applicable on creating table. thanks FreemanZ!
wyanjaspew
Advocate I
3 years agooh got it, doesn't applicable on creating table. thanks FreemanZ!
FreemanZ
Super User
3 years agoif you want the distinct list, try like:
DISTINCT(Table[Col])
or
VALUES(Table[Col])
or
ALL(Table[Col])