Forum Discussion
DAX Measure for Revenue average by Order
Hi,
I have a fact table like the one below. I need to create a measure calculating the average value of order (OrderKey)
| OrderNumber | CustomerCountry | OrderType | ProductNumber | SalesQuantity | SalesRevenue | OrderKey |
| 1 | US | XX | xc1353 | 56 | 42,540 | 1USXX |
| 1 | US | XX | vf4535 | 4 | 2,576 | 1USXX |
| 1 | US | XX | hg3563 | 44 | 45,562 | 1USXX |
| 1 | US | XX | kj7898 | 12 | 12,354 | 1USXX |
| 2 | UK | KY | vf4535 | 12 | 7,728 | 2UKKY |
| 2 | UK | KY | hg3563 | 123 | 127,367 | 2UKKY |
| 2 | UK | KY | kj7898 | 35 | 36,033 | 2UKKY |
Would you help?
try this:
Avg Order Revenue = AVERAGEX ( DISTINCT ( 'Table'[OrderKey] ), CALCULATE ( SUM ( 'Table'[SalesRevenue] ) ) )- Anonymous3 years ago
Hi zirael ,
Please have a try.
Create a measure.
ave_measure = AVERAGEX ( FILTER ( ALL ( 'Table' ), 'Table'[OrderNumber] = SELECTEDVALUE ( 'Table'[OrderNumber] ) ), 'Table'[SalesRevenue] )Or a column.
ave = AVERAGEX ( FILTER ( 'Table', 'Table'[OrderNumber] = EARLIER ( 'Table'[OrderNumber] ) ), 'Table'[SalesRevenue] )If I have misunderstood your meaning, please provide more details with your desired output.
Best Regards
Community Support Team _ Polly
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- Stachu
Community Champion
try this:
Avg Order Revenue = AVERAGEX ( DISTINCT ( 'Table'[OrderKey] ), CALCULATE ( SUM ( 'Table'[SalesRevenue] ) ) ) - AnonymousNot applicable
Hi zirael ,
Please have a try.
Create a measure.
ave_measure = AVERAGEX ( FILTER ( ALL ( 'Table' ), 'Table'[OrderNumber] = SELECTEDVALUE ( 'Table'[OrderNumber] ) ), 'Table'[SalesRevenue] )Or a column.
ave = AVERAGEX ( FILTER ( 'Table', 'Table'[OrderNumber] = EARLIER ( 'Table'[OrderNumber] ) ), 'Table'[SalesRevenue] )If I have misunderstood your meaning, please provide more details with your desired output.
Best Regards
Community Support Team _ Polly
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.