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Vinit
Frequent Visitor

DAX Divide Formula

Hi,

I want DAX formula for Divide,

it likes, Measure = No. of product / (no. of days between two dates - 1 - No. of Sundays in selected period)

 

Measure =

COUNT('Production of the day'[productshortname]) / (VALUES ( 'Production of the day'[actualendtime] )- 1 - no. of sundays)

 

how should i write Correct fromula for this.

Here is context of each term, 

No. of product = COUNT('Production of the day'[productshortname]),

no. of days between two dates =  (VALUES ( 'Production of the day'[actualendtime] ), 

1 = totals selected no. of days minus 1 day (it is value not text),

No. of Sundays in selected period = no. of sundays( how should i write DAX for no. of Sundays only)

 

1 ACCEPTED SOLUTION
Anonymous
Not applicable

Hi

Just count the number of days without sundays, it is easier

 

Working Days = 
CALCULATE(
    COUNTROWS('Date Table'), 
    FILTER('Date Table', 
        Not WEEKDAY('Date Table'[Date],2) in {7}
    )
)

View solution in original post

3 REPLIES 3
Anonymous
Not applicable

Hi,

 

Please give some samples of your data. Thks

Vinit_0-1665128811834.png

In the above image,

In Date, Both Date (01/09/2022) & (30/09/2022) are coming from same column

i.e. 'Production of the day'[actualendtime]

Below,     J961     SH1599     C18      BL5

              36.962    61.500     0.692    0.192

here for e.g. ,

J - Jeans(it is a product) , 961 - Total product count between 01/09/2022 & 30/09/2022, 

36.961 = 961/(30-4) i.e. 30- total selected days & 4 - no. of sundays between selected days(01/09/2022)&(30/09/2022).

 

here is contect , 

Production of the day'[productshortname] = J

COUNT('Production of the day'[productshortname]) = 961

VALUES ( 'Production of the day'[actualendtime] ) = 30

no. of sundays i.e. 01/09/2022 & 30/09/2022 = 4

( how should i write DAX for no. of Sundays only between any selected date)

 

So I required DAX formula for 36.961 i.e 961/(30-4) 

hope you get it.

Anonymous
Not applicable

Hi

Just count the number of days without sundays, it is easier

 

Working Days = 
CALCULATE(
    COUNTROWS('Date Table'), 
    FILTER('Date Table', 
        Not WEEKDAY('Date Table'[Date],2) in {7}
    )
)

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