Forum Discussion
DAX Calculate Countrows, average per Year per Weekday
- 4 years ago
Hi bkoenen ,
How about this:
Here the measure:
Average Countrows per Year per Weekday = VAR _helpTable = SUMMARIZE ( Table, Table[Day of the week], "NumberOfDayOfTheWeek", COUNT ( Table[Day of the week] ), "DistinctNumberOfDates", DISTINCTCOUNT ( Table[Date] ) ) RETURN MAXX (_helpTable, [NumberOfDayOfTheWeek] ) / MAXX (_helpTable, [DistinctNumberOfDates] )And here how the helpTable would look like:
Let me know if this helps or if you have any questions 🙂
/Tom
https://www.tackytech.blog/
https://www.instagram.com/tackytechtom/ - 4 years ago
Hi, bkoenen
You can try the following methods.
Measure:
Result = VAR _N1 = CALCULATE ( DISTINCTCOUNT ( 'Table'[Date] ), FILTER ( ALL ( 'Table' ), [Day of the week] = SELECTEDVALUE ( 'Table'[Day of the week] ) ) ) VAR _N2 = CALCULATE ( COUNT ( 'Table'[Day of the week] ), FILTER ( ALL ( 'Table' ), [Day of the week] = SELECTEDVALUE ( 'Table'[Day of the week] ) ) ) RETURN DIVIDE ( _N2, _N1 )COUNT: https://docs.microsoft.com/dax/count-function-dax
DISTINCTCOUNT: https://docs.microsoft.com/dax/distinctcount-function-dax
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
Hi, bkoenen
You can try the following methods.
Measure:
Result =
VAR _N1 =
CALCULATE (
DISTINCTCOUNT ( 'Table'[Date] ),
FILTER (
ALL ( 'Table' ),
[Day of the week] = SELECTEDVALUE ( 'Table'[Day of the week] )
)
)
VAR _N2 =
CALCULATE (
COUNT ( 'Table'[Day of the week] ),
FILTER (
ALL ( 'Table' ),
[Day of the week] = SELECTEDVALUE ( 'Table'[Day of the week] )
)
)
RETURN
DIVIDE ( _N2, _N1 )
COUNT: https://docs.microsoft.com/dax/count-function-dax
DISTINCTCOUNT: https://docs.microsoft.com/dax/distinctcount-function-dax
Best Regards,
Community Support Team _Charlotte
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.