Forum Discussion
Creating a column using two separate columns from different query.
Hello,
I have been trying to figure out how I can create a column that are based off of he date from 2 seperate columns that come from 2 seperate querys.
Example
Query/table 1 Query /table 2
ID # ID # a2
inital test final test 2
columm x columm y
Desired result (this table is visualizaton table created from multiple Tables )
ID # inital test Final test Status
123 pass "blank" In-process
124 "blank" "blank" "blank"
125 pass pass Ready
I need to create column in a table that says
If ID number passes final test it is ready if ID passes inital but final is blank than in process.
These two query are link to a third quarey by ID# so it did not alow me to creat a realtionship to each other.
Both Inital test and Final test are created based on other colmns with in their query/tables.
Can someone help with this?
- Anonymous6 years ago
why don't you merge two tables based on id's.
Then create calculated column for status.
Thanks & regards,
Pravin Wattamwar
www.linkedin.com/in/pravin-p-wattamwar
If I resolve your problem Mark it as a solution and give kudos. - Anonymous6 years ago
az38 Anonymous
So Feeling really stupid but I was able to just merge the columns and make it work. Sorry it only my 3week uring power bi now and Thank you both for all teh help.
11 Replies
- az38Community Champion
Hi Anonymous
try a LOOKUPVALUE() function, like
Status = var _initialStatus = LOOKUPVALUE('Table1'[initial test], [ID #], [ID #]) var _finalStatus = LOOKUPVALUE('Table2'[final test], [ID #], [ID #]) RETURN SWITCH(true(), NOT(ISBLANK(_finalStatus)), "Ready", NOT(ISBLANK(_initialStatus )) && ISBLANK(_finalStatus), "In-process", BLANK() )- AnonymousNot applicable
When i attempted this i got an error code
"A table of multiple values was supplied where a single value was expected."
When I creates a column using lookup it only transfered data for ID that final had and notthat ones that inital bad but final didnt.
- az38Community Champion
Anonymous
have you got any duplicated [ID #] value in your tables?