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BINewbie1's avatar
BINewbie1
Icon for Helper II rankHelper II
3 years ago
Solved

Counting comma delimited text strings

Hi there,   I have a field in my data model that represents a reason for something occuring. The field is is made up of between zero and up to nine strings of numbers, the field is formatted as tex...
Counting comma deiminated text strings
  • tamerj1's avatar
    tamerj1
    3 years ago

    BINewbie1 
    Looking at this screenshot I instantly realized my mistake. We need to filter the complete table as the VALUES of the column will return only distinct values and duplicates won't be counted.

    However, in the example that you have provided earlier, the first code would have produced 3 not 2. I will create a sample file to double check. For now please try

     

     

    Count Referal Text =
COUNTROWS (
    FILTER (
        CROSSJOIN (
            pre_referral,
            VALUES ( 'Lookup BBBC_referalreasonquestions_health'[Code] )
        ),
        CONTAINSSTRING (
            pre_referral[bbbc_referralreasonquestions_health],
            'Lookup BBBC_referalreasonquestions_health'[Code]
        )
    )
)

     

     

    *UPDATE

    Attached is the sample file


    Also make sure there is no relationship between the two tables. Some times it is automatically created without you even noticing. 

tamerj1's avatar
tamerj1
Icon for Community Champion rankCommunity Champion
3 years ago

BINewbie1 

It should work 😅

can you help me out with some screenshots?

BINewbie1's avatar
BINewbie1
Icon for Helper II rankHelper II
3 years ago

OK

 

Screen shot one is using the Measure Count Referal Text 2 using your Dax code, and the table displaying the data.

 

 

and screen shot two is using the Measure Count Referal Text, which uses the Dax code I borrowed from youtube, which is a bit closer, but its only counting the strings when they appear on their own in a cell, not when in a long list of other strings.

 

 

Hope that's viewable - if not i'll enlarge them.

 

Thanks!


Adam

  • BINewbie1's avatar
    BINewbie1
    Icon for Helper II rankHelper II
    3 years ago

    Thanks Tamerj1,

     

    That seems to be working fine now.

     

    There's was a relationship between the tables and turning it off seems to have done the trick.

     

    I also now know that there's isn't a 10th code for other - suspect the free text for other is kept somewhere else in the system.

     

    Many thanks for all you work - its really appreciated!,

     

    Adam

  • BINewbie1's avatar
    BINewbie1
    Icon for Helper II rankHelper II
    3 years ago

    Sorry here's a third screen shot with the fields atually as you wrote the code. I swapped them around just to check. But it made no difference.

     

  • tamerj1's avatar
    tamerj1
    Icon for Community Champion rankCommunity Champion
    3 years ago

    BINewbie1 
    Looking at this screenshot I instantly realized my mistake. We need to filter the complete table as the VALUES of the column will return only distinct values and duplicates won't be counted.

    However, in the example that you have provided earlier, the first code would have produced 3 not 2. I will create a sample file to double check. For now please try

     

     

    Count Referal Text =
COUNTROWS (
    FILTER (
        CROSSJOIN (
            pre_referral,
            VALUES ( 'Lookup BBBC_referalreasonquestions_health'[Code] )
        ),
        CONTAINSSTRING (
            pre_referral[bbbc_referralreasonquestions_health],
            'Lookup BBBC_referalreasonquestions_health'[Code]
        )
    )
)

     

     

    *UPDATE

    Attached is the sample file


    Also make sure there is no relationship between the two tables. Some times it is automatically created without you even noticing.