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  <channel>
    <title>topic Re: want to get top n number of columns based on the highest to lowest value in Power Query</title>
    <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310996#M106941</link>
    <description>&lt;P&gt;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="583044" data-lia-user-login="muhammadfaisal" class="lia-mention lia-mention-user"&gt;muhammadfaisal&lt;/a&gt;&amp;nbsp;try this&lt;/P&gt;&lt;LI-CODE lang="markup"&gt;let
    Source = your_table,
    types = Table.TransformColumnTypes(Source,{{"date", type date}}),
    sort = Table.Sort(types,{{"date", Order.Ascending}}),
//  list of currency codes
    ccy_lst = List.Buffer(List.Skip(Table.ColumnNames(sort))),
//  this is a list of ccy &amp;amp; List.Max combinations to use in grouping later
    find_max = List.Transform(ccy_lst, (x) =&amp;gt; {x, (y) =&amp;gt; List.Max(Table.Column(y, x))}),
//  group data by year and find max of each currency value (rate?)
    group_by_year = 
        Table.Group(
            sort, "date", 
            find_max,
            GroupKind.Local, 
            (s, c) =&amp;gt; Number.From(Date.Year(s) &amp;lt;&amp;gt; Date.Year(c))
        ),
//  bring ccy columns to single column to group by year later
    unpivot = Table.UnpivotOtherColumns(group_by_year, {"date"}, "Ccy", "Max Value"),
    get_year = Table.TransformColumns(unpivot, {"date", Date.Year}),
//  group by year, sort by value and get top 5
    group_again = Table.Group(get_year, {"date"}, {{"top5", each Table.FirstN(Table.Sort(_, {"Max Value", Order.Descending}), 5)}}),
    expand = Table.ExpandTableColumn(group_again, "top5", {"Ccy", "Max Value"}, {"Ccy", "Max Value"}),
    rename = Table.RenameColumns(expand, {"date", "Year"})
in
    rename&lt;/LI-CODE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
    <pubDate>Sat, 01 Jul 2023 05:30:40 GMT</pubDate>
    <dc:creator>AlienSx</dc:creator>
    <dc:date>2023-07-01T05:30:40Z</dc:date>
    <item>
      <title>want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310375#M106903</link>
      <description>&lt;P&gt;Hi folks&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;i will be really grateful if someone can help me with a problem. I have a csv file (exchanges.csv) that contatins total 55 columns. first column is date and other 54 columns are actually currency codes of different countries. currency columns have numeric data for each date.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;i want to write a code in power query to show top 5 currency codes based on the top 5 highest values among all 54 currencies for each calendar year. Also i want to see the maximum value based on which currency qualified for top 5. so there will be three columns.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Column 1: Year&lt;/P&gt;&lt;P&gt;Column 2: Currecny code&lt;/P&gt;&lt;P&gt;Column 3: Actual data value (maximum value)&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Thanks&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Fri, 30 Jun 2023 14:24:23 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310375#M106903</guid>
      <dc:creator>muhammadfaisal</dc:creator>
      <dc:date>2023-06-30T14:24:23Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310517#M106915</link>
      <description>&lt;P&gt;hi,&amp;nbsp;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="583044" data-lia-user-login="muhammadfaisal" class="lia-mention lia-mention-user"&gt;muhammadfaisal&lt;/a&gt;&amp;nbsp;please show your data. Don't need to show all 55 columns. 3-4 columns and 3-4 rows is enough. It's not clear if any single row represents a summary of all year or just a one of the dates of that year.&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Fri, 30 Jun 2023 15:41:31 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310517#M106915</guid>
      <dc:creator>AlienSx</dc:creator>
      <dc:date>2023-06-30T15:41:31Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310584#M106917</link>
      <description>&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;TABLE border="1"&gt;&lt;TBODY&gt;&lt;TR&gt;&lt;TD&gt;date&lt;/TD&gt;&lt;TD&gt;ARS&lt;/TD&gt;&lt;TD&gt;AUD&lt;/TD&gt;&lt;TD&gt;BHD&lt;/TD&gt;&lt;TD&gt;BWP&lt;/TD&gt;&lt;TD&gt;BRL&lt;/TD&gt;&lt;TD&gt;BND&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/27/2023&lt;/TD&gt;&lt;TD&gt;255.1565&lt;/TD&gt;&lt;TD&gt;1.496622&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.36798&lt;/TD&gt;&lt;TD&gt;4.804374&lt;/TD&gt;&lt;TD&gt;1.348996&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/26/2023&lt;/TD&gt;&lt;TD&gt;253.5373&lt;/TD&gt;&lt;TD&gt;1.496783&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.39429&lt;/TD&gt;&lt;TD&gt;4.769887&lt;/TD&gt;&lt;TD&gt;1.353372&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/26/2023&lt;/TD&gt;&lt;TD&gt;252.3788&lt;/TD&gt;&lt;TD&gt;1.498107&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.39621&lt;/TD&gt;&lt;TD&gt;4.766984&lt;/TD&gt;&lt;TD&gt;1.352252&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/25/2023&lt;/TD&gt;&lt;TD&gt;253.0808&lt;/TD&gt;&lt;TD&gt;1.496756&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.787164&lt;/TD&gt;&lt;TD&gt;1.35193&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/25/2023&lt;/TD&gt;&lt;TD&gt;253.0807&lt;/TD&gt;&lt;TD&gt;1.497643&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.787163&lt;/TD&gt;&lt;TD&gt;1.35193&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/24/2023&lt;/TD&gt;&lt;TD&gt;253.0389&lt;/TD&gt;&lt;TD&gt;1.497103&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.784586&lt;/TD&gt;&lt;TD&gt;1.350962&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/24/2023&lt;/TD&gt;&lt;TD&gt;253.0356&lt;/TD&gt;&lt;TD&gt;1.496323&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32386&lt;/TD&gt;&lt;TD&gt;4.785148&lt;/TD&gt;&lt;TD&gt;1.351308&lt;/TD&gt;&lt;TD&gt;&amp;nbsp;&lt;/TD&gt;&lt;/TR&gt;&lt;/TBODY&gt;&lt;/TABLE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Fri, 30 Jun 2023 16:37:28 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310584#M106917</guid>
      <dc:creator>muhammadfaisal</dc:creator>
      <dc:date>2023-06-30T16:37:28Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310591#M106918</link>
      <description>&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;TABLE border="1"&gt;&lt;TBODY&gt;&lt;TR&gt;&lt;TD&gt;date&lt;/TD&gt;&lt;TD&gt;ARS&lt;/TD&gt;&lt;TD&gt;AUD&lt;/TD&gt;&lt;TD&gt;BHD&lt;/TD&gt;&lt;TD&gt;BWP&lt;/TD&gt;&lt;TD&gt;BRL&lt;/TD&gt;&lt;TD&gt;BND&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/27/2023&lt;/TD&gt;&lt;TD&gt;255.1565&lt;/TD&gt;&lt;TD&gt;1.496622&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.36798&lt;/TD&gt;&lt;TD&gt;4.804374&lt;/TD&gt;&lt;TD&gt;1.348996&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/26/2023&lt;/TD&gt;&lt;TD&gt;253.5373&lt;/TD&gt;&lt;TD&gt;1.496783&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.39429&lt;/TD&gt;&lt;TD&gt;4.769887&lt;/TD&gt;&lt;TD&gt;1.353372&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/26/2023&lt;/TD&gt;&lt;TD&gt;252.3788&lt;/TD&gt;&lt;TD&gt;1.498107&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.39621&lt;/TD&gt;&lt;TD&gt;4.766984&lt;/TD&gt;&lt;TD&gt;1.352252&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/25/2023&lt;/TD&gt;&lt;TD&gt;253.0808&lt;/TD&gt;&lt;TD&gt;1.496756&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.787164&lt;/TD&gt;&lt;TD&gt;1.35193&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/25/2023&lt;/TD&gt;&lt;TD&gt;253.0807&lt;/TD&gt;&lt;TD&gt;1.497643&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.787163&lt;/TD&gt;&lt;TD&gt;1.35193&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/24/2023&lt;/TD&gt;&lt;TD&gt;253.0389&lt;/TD&gt;&lt;TD&gt;1.497103&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32387&lt;/TD&gt;&lt;TD&gt;4.784586&lt;/TD&gt;&lt;TD&gt;1.350962&lt;/TD&gt;&lt;/TR&gt;&lt;TR&gt;&lt;TD&gt;6/24/2023&lt;/TD&gt;&lt;TD&gt;253.0356&lt;/TD&gt;&lt;TD&gt;1.496323&lt;/TD&gt;&lt;TD&gt;0.376&lt;/TD&gt;&lt;TD&gt;13.32386&lt;/TD&gt;&lt;TD&gt;4.785148&lt;/TD&gt;&lt;TD&gt;1.351308&lt;/TD&gt;&lt;/TR&gt;&lt;/TBODY&gt;&lt;/TABLE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Fri, 30 Jun 2023 16:40:45 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310591#M106918</guid>
      <dc:creator>muhammadfaisal</dc:creator>
      <dc:date>2023-06-30T16:40:45Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310598#M106920</link>
      <description>&lt;P&gt;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="532285" data-lia-user-login="AlienSx" class="lia-mention lia-mention-user"&gt;AlienSx&lt;/a&gt;&amp;nbsp;i do have this query which is showing grouped data on year basis with maximum value. the only problem is that it is not picking currency column based on the maximum value. rather it is only showing top 5 on alphabetical order.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;let&lt;BR /&gt;Source = exchanges, // Replace "exchanges" with the actual name of your loaded table&lt;/P&gt;&lt;P&gt;// Add a custom column with the calendar year&lt;BR /&gt;CustomYear = Table.AddColumn(Source, "Year", each Date.Year([date])),&lt;/P&gt;&lt;P&gt;// Group the data by calendar year and get the names of top 5 columns with maximum values&lt;BR /&gt;GroupedData = Table.Group(CustomYear, {"Year"},&lt;BR /&gt;{{"TopColumns", each List.FirstN(List.Sort(Table.ColumnNames(Table.RemoveColumns(_, {"date"}))), 5), type list}}&lt;BR /&gt;),&lt;/P&gt;&lt;P&gt;// Expand the TopColumns list to individual columns&lt;BR /&gt;ExpandedColumns = Table.ExpandListColumn(GroupedData, "TopColumns"),&lt;/P&gt;&lt;P&gt;// Select the calendar year and the top 5 columns from the original table&lt;BR /&gt;SelectedColumns = Table.SelectColumns(ExpandedColumns, {"Year", "TopColumns"}),&lt;/P&gt;&lt;P&gt;// Retrieve the maximum value for each column in the corresponding calendar year&lt;BR /&gt;MaxValues = Table.AddColumn(SelectedColumns, "MaxValue", each List.Max(Table.Column(Source, [TopColumns]))),&lt;/P&gt;&lt;P&gt;// Reorder the columns for better visibility (Year, Column Name, Max Value)&lt;BR /&gt;ReorderedColumns = Table.ReorderColumns(MaxValues, {"Year", "TopColumns", "MaxValue"})&lt;BR /&gt;in&lt;BR /&gt;ReorderedColumns&lt;/P&gt;</description>
      <pubDate>Fri, 30 Jun 2023 16:45:47 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310598#M106920</guid>
      <dc:creator>muhammadfaisal</dc:creator>
      <dc:date>2023-06-30T16:45:47Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310996#M106941</link>
      <description>&lt;P&gt;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="583044" data-lia-user-login="muhammadfaisal" class="lia-mention lia-mention-user"&gt;muhammadfaisal&lt;/a&gt;&amp;nbsp;try this&lt;/P&gt;&lt;LI-CODE lang="markup"&gt;let
    Source = your_table,
    types = Table.TransformColumnTypes(Source,{{"date", type date}}),
    sort = Table.Sort(types,{{"date", Order.Ascending}}),
//  list of currency codes
    ccy_lst = List.Buffer(List.Skip(Table.ColumnNames(sort))),
//  this is a list of ccy &amp;amp; List.Max combinations to use in grouping later
    find_max = List.Transform(ccy_lst, (x) =&amp;gt; {x, (y) =&amp;gt; List.Max(Table.Column(y, x))}),
//  group data by year and find max of each currency value (rate?)
    group_by_year = 
        Table.Group(
            sort, "date", 
            find_max,
            GroupKind.Local, 
            (s, c) =&amp;gt; Number.From(Date.Year(s) &amp;lt;&amp;gt; Date.Year(c))
        ),
//  bring ccy columns to single column to group by year later
    unpivot = Table.UnpivotOtherColumns(group_by_year, {"date"}, "Ccy", "Max Value"),
    get_year = Table.TransformColumns(unpivot, {"date", Date.Year}),
//  group by year, sort by value and get top 5
    group_again = Table.Group(get_year, {"date"}, {{"top5", each Table.FirstN(Table.Sort(_, {"Max Value", Order.Descending}), 5)}}),
    expand = Table.ExpandTableColumn(group_again, "top5", {"Ccy", "Max Value"}, {"Ccy", "Max Value"}),
    rename = Table.RenameColumns(expand, {"date", "Year"})
in
    rename&lt;/LI-CODE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Sat, 01 Jul 2023 05:30:40 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3310996#M106941</guid>
      <dc:creator>AlienSx</dc:creator>
      <dc:date>2023-07-01T05:30:40Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3311207#M106953</link>
      <description>&lt;P&gt;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="532285" data-lia-user-login="AlienSx" class="lia-mention lia-mention-user"&gt;AlienSx&lt;/a&gt;&amp;nbsp;thanks for your helps. it just worked the way i wanted. Kudos!&lt;/P&gt;</description>
      <pubDate>Sat, 01 Jul 2023 20:24:05 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3311207#M106953</guid>
      <dc:creator>muhammadfaisal</dc:creator>
      <dc:date>2023-07-01T20:24:05Z</dc:date>
    </item>
    <item>
      <title>Re: want to get top n number of columns based on the highest to lowest value</title>
      <link>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3694318#M121474</link>
      <description>&lt;P&gt;Hi&amp;nbsp;&lt;a href="javascript:void(0)" data-lia-user-mentions="" data-lia-user-uid="583044" data-lia-user-login="muhammadfaisal" class="lia-mention lia-mention-user"&gt;muhammadfaisal&lt;/a&gt;,&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;This code shows TOP5 of all time. If you want to show TOP5 of every year - let me know.&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;P&gt;Result:&lt;/P&gt;&lt;P&gt;&lt;img /&gt;&lt;/P&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;&lt;LI-CODE lang="javascript"&gt;let
    Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("fdBLDoMwDATQu7BGIfH4exbE/a9RlyZtodCdFcVPM17XSReyhSphmicSKU1UcmyFQ5Uox1pg+nxCgVp4jly8Moz3j2CP0Gmbd0w/GIrAMDBznLBgih0zDXd7YQIYXWCUi+4d81btjCm1jqXWkwnl4sDkO1n16u9koieMsMdJzK3pwFrgzrJumfK55dHCr8UHCx7DavWPxeLarZrdbzDRURJ0gWnHpLGPYMjDbNsD", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [date = _t, ARS = _t, AUD = _t, BHD = _t, BWP = _t, BRL = _t, BND = _t]),
    ChangedTypesDynamic = Table.TransformColumns(Source, 
      //Dates
      List.Transform(
          List.Select(Table.ColumnNames(Source), each Text.Contains(_, "date", Comparer.OrdinalIgnoreCase)),
          (colName)=&amp;gt; { colName, each Date.From(_, "en-US"), type date }
      ) &amp;amp; 
      //Currencies
      List.Transform( 
          List.Select(Table.ColumnNames(Source), each not Text.Contains(_, "date", Comparer.OrdinalIgnoreCase)),
          (colName)=&amp;gt; { colName, each Number.From(_, "en-US"), type number }
      )
),
    #"Extracted Year" = Table.TransformColumns(ChangedTypesDynamic,{{"date", Date.Year, Int64.Type}}),
    #"Renamed Columns" = Table.RenameColumns(#"Extracted Year",{{"date", "Year"}}),
    #"Unpivoted Other Columns" = Table.UnpivotOtherColumns(#"Renamed Columns", {"Year"}, "Currency", "Value"),
    #"Grouped Rows" = Table.Group(#"Unpivoted Other Columns", {"Year", "Currency"}, {{"Max Value", each List.Max([Value]), type number}}),
    #"Sorted Rows" = Table.Sort(#"Grouped Rows",{{"Max Value", Order.Descending}}),
    #"Kept First Rows" = Table.FirstN(#"Sorted Rows",5)
in
    #"Kept First Rows"&lt;/LI-CODE&gt;&lt;P&gt;&amp;nbsp;&lt;/P&gt;</description>
      <pubDate>Mon, 12 Feb 2024 15:00:24 GMT</pubDate>
      <guid>https://community.fabric.microsoft.com/t5/Power-Query/want-to-get-top-n-number-of-columns-based-on-the-highest-to/m-p/3694318#M121474</guid>
      <dc:creator>dufoq3</dc:creator>
      <dc:date>2024-02-12T15:00:24Z</dc:date>
    </item>
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