topic How to get a specific date in DAX Commands and Tips

How to get a specific date

Anonymous — Mon, 02 May 2022 18:27:40 GMT

I have a column I need to filter. As of Now I have it like this:

BeforeToday_MI = IF(Query_Util[MoveInDate].[Date] < TODAY(), True, False)

It returns True if MoveInDate column has dates prior to today. However, I want the function to return true if the date is before Today AND the day is not Saturday or Sunday; in other words, the date belong to a weekday and not a weekend.

I tried this but it's giving me error:

BeforeToday_MI = IF(Query_Util[MoveInDate].[Date] < TODAY() && VALUE(Query_Util[MoveInDate].[Day]) <> "Saturday", True, False)

Re: How to get a specific date

amitchandak — Tue, 03 May 2022 01:27:36 GMT

Anonymous ,

BeforeToday_MI = IF( datevalues(Query_Util[MoveInDate]) < TODAY() && weekday(Query_Util[MoveInDate],2) <6 , True, False)

Re: How to get a specific date

Anonymous — Wed, 04 May 2022 15:57:21 GMT

What if I want to get the days that are not Saturday or Sunday?

(My bad; I forgot to include that specification before. I need work days. Your code works perfectly; I just need to act the condition of filtering out Sunday as well.)

Re: How to get a specific date

v-chenwuz-msft — Thu, 05 May 2022 10:09:08 GMT

Hi Anonymous ,

Did you get your problem solved? If it was solved, please mark it as a solution so that more people can find it. If not, refer to the following.

weekday(Query_Util[MoveInDate],2) return result follow the following rule.

week begins on Monday (1) and ends on Sunday (7).

If you only want filter out sunday, then weekday(Query_Util[MoveInDate],2) <7. Or enter the day you want like this:

weekday(Query_Util[MoveInDate],2) = 1 &&

weekday(Query_Util[MoveInDate],2) = 2 &&

weekday(Query_Util[MoveInDate],2) = 3 &&

weekday(Query_Util[MoveInDate],2) = 4

More detail you can refer this function.

WEEKDAY function (DAX) - DAX | Microsoft Docs

Best Regards

Community Support Team _ chenwu zhu

If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.