topic Re: UNION Filtered Data and then RANKX in DAX Commands and Tips

UNION Filtered Data and then RANKX

Anonymous — Wed, 05 Jan 2022 17:30:27 GMT

Hello,

I'm trying to create a rank between data from 2 tables

table 1

Company	Category	value
A	YY	5
A	ZZ	1
B	YY	3
B	ZZ	4

table 2

Company	Type	Category	Value
C	1	YY	1
C	1	ZZ	2
D	1	YY	4
D	1	ZZ	3
E	2	ZZ	2
F	2	ZZ	3

On a page I have filters for both of them, for example, on table 1 I filtered to show only company A and on table 2 I filtered to show only Type 1.

What I need is to show the rank of company A, using the value, of all categories, and rank with the values of table 2. The result should be:

Company	Category	Value	Rank
A	YY	5	3
A	ZZ	1	1

How can I do this?

Thank you

Re: UNION Filtered Data and then RANKX

VahidDM — Wed, 05 Jan 2022 23:00:08 GMT

Hi Anonymous

Can you add more details re how you find the rank numbers in the result table?

It's not that clear!

Appreciate your Kudos!!
LinkedIn: www.linkedin.com/in/vahid-dm/

Re: UNION Filtered Data and then RANKX

Anonymous — Thu, 06 Jan 2022 09:35:39 GMT

Hi,

It is the rank looking at the values, higher the value higher the rank.

I was trying to do this

r des =
var tb = union(SUMMARIZE('Table 2',"category",MAX('Table 2'[category]),"company",max('Table 2'[company]),"value",sum('Table 2'[value])),
SUMMARIZE('Table 1',"category",MAX('Table 1'[category]),"company",max('Table 1'[company]),"value",sum('Table 1'[value]))
)
return RANKX(tb,[value],,0)

But it says that there is no value on "value"

Thank you

Re: UNION Filtered Data and then RANKX

Anonymous — Thu, 06 Jan 2022 11:51:33 GMT

I don't know if it helps, but table 1 and table 2 are actually duplicated tables, so they are the same.

I use table 1 to show calculate measures of the company and table 2 to calculate measures of a filtered group of companies in a type.

In this case I want to show the company, category, value and the rank of the value, of that company, within the values of the companies that are filtered by a type, so for company A and category YY should calculate the rank of this value and all the values of the companies with same category and filtered type 1 and the calculated rank shoul be 3. It is the same thing for company A and category ZZ and the rank should be 1

Re: UNION Filtered Data and then RANKX

Anonymous — Fri, 07 Jan 2022 13:32:31 GMT

I'm trying something like this

Rank 2 = RANKX(

filter(

all('Table 2'[Company],'Table 2'[Type],'Table 2'[Category]),

'Table 2'[Category]=SELECTEDVALUE('Table 1'[Category]) &&

('Table 2'[Company]=SELECTEDVALUE('Table 1'[Company]) ||

'Table 2'[Type]=SELECTEDVALUE('Table 2'[Type]))),

'Table 2'[Total Value],,0)

but it allways returns 1 😕

anyone can help?

Thank you

Re: UNION Filtered Data and then RANKX

v-xiaotang — Mon, 10 Jan 2022 05:25:26 GMT

Hi Anonymous

Best Regards,

Community Support Team _Tang

If this post helps, please consider Accept it as the solution to help the other members find it more quickly.

Re: UNION Filtered Data and then RANKX

Anonymous — Mon, 10 Jan 2022 07:58:30 GMT

Hello,

I forgot to say that there os a relationship between them in categoria, so the first line will only look for category YY on table 2 and the second line for category ZZ

Re: UNION Filtered Data and then RANKX

v-xiaotang — Tue, 11 Jan 2022 03:06:03 GMT

Hi Anonymous

Try this,

DAX code:

Measure = var __category = SELECTEDVALUE(Table1[Category]) var __table1 = SELECTCOLUMNS(Table1,"Company",Table1[Company],"Category",Table1[Category],"Value",Table1[value]) var __table2 = SELECTCOLUMNS(FILTER(Table2,Table2[Category]=__category),"Company",Table2[Company],"Category",Table2[Category],"Value",Table2[Value]) var __table3 = UNION(__table1,__table2) var __table4 = ADDCOLUMNS(__table3,"rank",RANKX(__table3,[Value],,ASC)) return MAXX(FILTER(__table4,[Company]=SELECTEDVALUE(Table1[Company])),[rank])

This measure is designed based on the sample data and expected results you provide. If requirements change, you can adjust the measure .

Best Regards,

Community Support Team _Tang

If this post helps, please consider Accept it as the solution to help the other members find it more quickly.