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LeaRupnik's avatar
LeaRupnik
Helper III
3 years ago
Solved

sum condition

Hello,

I have one question regarding dax, do you maybe know how I could calculate this to get the following

in a sum i like NEplačano 8670677 and not 8086893. I have a dax

Neplačano v tožbi:=IF([Plačano v tožbi]>[Fakturirano v tožbi],0,SUMX('receivables terjatve',[Fakturirano v tožbi]-[Plačano v tožbi]))

 

  • Anonymous's avatar
    Anonymous
    3 years ago

    Hi LeaRupnik 

     

     According to the data and requirements you provided, you can not get the calculation results you want, I found several inaccuracies in the picture, you can refer to the comparison chart I provided

     

     

     

     

    Here is my computed column code

    NT = IF('Table'[PT]>'Table'[FT],0,'Table'[FT]-'Table'[PT])

    Sum_NT = SUM('Table'[NT])

     

     

     

    Best Regards,

    Yolo Zhu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

2 Replies

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi LeaRupnik 

     

     According to the data and requirements you provided, you can not get the calculation results you want, I found several inaccuracies in the picture, you can refer to the comparison chart I provided

     

     

     

     

    Here is my computed column code

     NT = IF('Table'[PT]>'Table'[FT],0,'Table'[FT]-'Table'[PT])

    Sum_NT = SUM('Table'[NT])

     

     

     

    Best Regards,

    Yolo Zhu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi LeaRupnik 

     

     According to the data and requirements you provided, you can not get the calculation results you want, I found several inaccuracies in the picture, you can refer to the comparison chart I provided

     

     

     

     

    Here is my computed column code

    NT = IF('Table'[PT]>'Table'[FT],0,'Table'[FT]-'Table'[PT])

    Sum_NT = SUM('Table'[NT])

     

     

     

    Best Regards,

    Yolo Zhu

    If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.