Forum Discussion
Anonymous
5 years agoNot applicable
Split multiple columns using deliminator
Column name: Unit-cost is split by using the below command. = Table.SplitColumn(#"Filtered rows- Invoice posted from 2017", "Unit-cost", Splitter.SplitTextByEachDelimiter({";"}, QuoteStyle.Csv, ...
- Anonymous5 years ago
for the moment there is no "s" at the end of Table.SplitColumn. While waiting for MS to add this letter, you could use something like:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("HYu5EYAwEMR6uRgFPA3QAf8AHgcG3xWAA7ePIdLMauWchJQws4AFI2uWSgIXd2G/c3CKr5zok5UUsVj2moa2cGVj+XVSolnk0e7ra66G+7vMDIxM4v0L", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t, Column3 = _t]), colsToSplit=Table.ColumnNames(Source), #"Split ColumnS by Delimiter" = List.Accumulate(colsToSplit,Source,(s,c)=> Table.SplitColumn(s, c, Splitter.SplitTextByDelimiter("-", QuoteStyle.Csv))) in #"Split ColumnS by Delimiter"
Anonymous
5 years agoNot applicable
for the moment there is no "s" at the end of Table.SplitColumn. While waiting for MS to add this letter, you could use something like:
let
Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("HYu5EYAwEMR6uRgFPA3QAf8AHgcG3xWAA7ePIdLMauWchJQws4AFI2uWSgIXd2G/c3CKr5zok5UUsVj2moa2cGVj+XVSolnk0e7ra66G+7vMDIxM4v0L", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [Column1 = _t, Column2 = _t, Column3 = _t]),
colsToSplit=Table.ColumnNames(Source),
#"Split ColumnS by Delimiter" = List.Accumulate(colsToSplit,Source,(s,c)=> Table.SplitColumn(s, c, Splitter.SplitTextByDelimiter("-", QuoteStyle.Csv)))
in
#"Split ColumnS by Delimiter"