Forum Discussion
Power Query - create multiple rows
Hi - I would like to do the following - create a row for each value in a field.
Example:
| ID | Food Type |
| 1 | Ice Cream; Cake; Cookies |
| 2 | Apples; Bananas; Pears; Peaches |
| 3 | Pizza |
Output:
| ID | Food Type |
| 1 | Ice Cream |
| 1 | Cake |
| 1 | Cookies |
| 2 | Apples |
| 2 | Bananas |
| 2 | Peaches |
| 2 | Pears |
| 3 | Pizza |
Therefore, the ";" indicates a new record (so to speak) - any thoughts ? Jerry
Source
You turn the string into a List, and then expand it:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUfJMTlVwLkpNzLVWcE7MTgWS+fnZmanFSrE60UpGQAWOBQU5qcXWCk6JeUAIZASkJhZBqOQMqDpjoLqAzKqqRKXYWAA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, #"Food Type" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"ID", Int64.Type}, {"Food Type", type text}}), #"Create List" = Table.TransformColumns(#"Changed Type",{"Food Type", each Text.Split(_,";"),type {text}}), #"Expanded Food Type" = Table.ExpandListColumn(#"Create List", "Food Type") in #"Expanded Food Type"Result
jerryr125 Many ways to solve this, here is one using List.TransformMany
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUfJMTlVwLkpNzLVWcE7MTgWS+fnZmanFSrE60UpGQAWOBQU5qcXWCk6JeUAIZASkJhZBqOQMqDpjoLqAzKqqRKXYWAA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, #"Food Type" = _t]), ChangedType = Table.TransformColumnTypes ( Source, { { "ID", Int64.Type } } ), Transform = List.TransformMany ( Table.ToRows ( ChangedType ), ( z ) => Text.SplitAny ( z{1}, ";" ), ( x, y ) => { x{0}, y } ), ToTable = Table.FromRows ( Transform, type table [ ID = Int64.Type, Food Type = text ] ) in ToTableHi jerryr125 , you can solve this problem by UI, just select the column Food Type, go to the homw tab, select Split Column by delimiter and make the setting presented in the below picture (it is important to select by row)
4 Replies
- ronrsnfldSuper User
Source
You turn the string into a List, and then expand it:
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUfJMTlVwLkpNzLVWcE7MTgWS+fnZmanFSrE60UpGQAWOBQU5qcXWCk6JeUAIZASkJhZBqOQMqDpjoLqAzKqqRKXYWAA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, #"Food Type" = _t]), #"Changed Type" = Table.TransformColumnTypes(Source,{{"ID", Int64.Type}, {"Food Type", type text}}), #"Create List" = Table.TransformColumns(#"Changed Type",{"Food Type", each Text.Split(_,";"),type {text}}), #"Expanded Food Type" = Table.ExpandListColumn(#"Create List", "Food Type") in #"Expanded Food Type"Result
- AntrikshSharmaCommunity Champion
jerryr125 Many ways to solve this, here is one using List.TransformMany
let Source = Table.FromRows(Json.Document(Binary.Decompress(Binary.FromText("i45WMlTSUfJMTlVwLkpNzLVWcE7MTgWS+fnZmanFSrE60UpGQAWOBQU5qcXWCk6JeUAIZASkJhZBqOQMqDpjoLqAzKqqRKXYWAA=", BinaryEncoding.Base64), Compression.Deflate)), let _t = ((type nullable text) meta [Serialized.Text = true]) in type table [ID = _t, #"Food Type" = _t]), ChangedType = Table.TransformColumnTypes ( Source, { { "ID", Int64.Type } } ), Transform = List.TransformMany ( Table.ToRows ( ChangedType ), ( z ) => Text.SplitAny ( z{1}, ";" ), ( x, y ) => { x{0}, y } ), ToTable = Table.FromRows ( Transform, type table [ ID = Int64.Type, Food Type = text ] ) in ToTable - Omid_MotamediseSuper User
Hi jerryr125 , you can solve this problem by UI, just select the column Food Type, go to the homw tab, select Split Column by delimiter and make the setting presented in the below picture (it is important to select by row)
- jerryr125Helper IV
Hi - I did a split then a unpivot and solved it - thanks so much - Jerry