Forum Discussion
IP address conversion
Hi
I have a column with IP address
I want to do following:
Excample Ip address 172.180.180.34
Octet 2
Take the number from octet 2 and substract it with 176. Get the number and choose a character from a variabel
Variabel = "0123456789abcdefghijklmnopqrstuvwxyz"
So if the octet 2 is 180 the result would be:
180-176 = 4
Value after postion 4 from the variabel = 4
Octet3
Convert the number to hex
So octet 3 is 180 and would be B4
Result in new column
result octet 2+result octet 3
3B4
Hi desperado ,
Then use below code:
let IP2Number = ( IP as text ) => let currentIP = IP, Alfa = {"0".."9"} & {"A".."Z"}, ListOfOctets = Text.Split(currentIP, "."), Octet2 = Alfa{Value.Subtract(Value.FromText(ListOfOctets{1}),176)}, Octet3 = Number.ToText(Value.FromText(ListOfOctets{2}), "x"), Result = try Text.Combine({Octet2, Octet3}) otherwise "unknown" in Result in IP2NumberAnd you will see:
For the updated .pbix file,pls see attached.
Best Regards,
KellyDid I answer your question? Mark my post as a solution!
5 Replies
- desperadoRegular Visitor
Ladies & Gents
This is my first Power Query function.
Based on above scenario here is what I figured out.
-------------------------------------------------------let
IP2Number = (IP as text
) => letcurrentIP = IP,
Alfa = {"0".."9"} & {"A".."Z"},
ListOfOctets = Text.Split(currentIP, "."),
Octet2 = Alfa{Value.Subtract(Value.FromText(ListOfOctets{1}),176)},
Octet3 = Number.ToText(Value.FromText(ListOfOctets{2}), "x"),
Result = Text.Combine({Octet2, Octet3})
in
Result
in
IP2Number-------------------------------------
Please le me know if it's correct thinking
- desperadoRegular Visitor
After testing, I need to have a check on the value of octet2.
If the value of octet2 is negativ, then Result should be "unknown"
Not familiar with if's ....- v-kelly-msftCommunity Support
Hi desperado ,
Modify your M code as below:
let IP2Number = ( IP as text ) => let currentIP = IP, Alfa = {"0".."9"} & {"A".."Z"}, ListOfOctets = Text.Split(currentIP, "."), Octet2 = try Alfa{Value.Subtract(Value.FromText(ListOfOctets{1}),176)} otherwise "unknown", Octet3 = Number.ToText(Value.FromText(ListOfOctets{2}), "x"), Result = Text.Combine({Octet2, Octet3}) in Result in IP2NumberAnd you will see:
For the related .pbix file,pls see attached.
Best Regards,
KellyDid I answer your question? Mark my post as a solution!