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Anonymous's avatar
Anonymous
Not applicable
8 years ago
Solved

Integer Extraction function returning Expression.Error Message

Through some research, I found this formula to extract numbers only to use in my queries. Since it is used often, I want to write a function from it. However, I can't seem to make it work properly. I...
  • Anonymous's avatar
    Anonymous
    8 years ago

    Anonymous,

    Please check the following code.

    let intextaction=(AlphaNumeric as  text)=>

let
    Source = Text.Combine(List.RemoveNulls(List.Transform(Text.ToList(""&AlphaNumeric&""),each if Value.Is(Value.FromText(_), type number) then _ else null)))
in
    Source

in
   intextaction



    Regards,
    Lydia

Anonymous's avatar
Anonymous
Not applicable
8 years ago

Anonymous,

Please check the following code.

let intextaction=(AlphaNumeric as  text)=>

let
    Source = Text.Combine(List.RemoveNulls(List.Transform(Text.ToList(""&AlphaNumeric&""),each if Value.Is(Value.FromText(_), type number) then _ else null)))
in
    Source

in
   intextaction



Regards,
Lydia

  • Anonymous's avatar
    Anonymous
    Not applicable
    8 years ago

    Lydia,

     

    Thank you, this solved the problem. After looking closely, the List.Transform method requires an "each" statement (not sure if that's how you say it "each statement"?).

     

    The AlphaNumeric variable can go in there without having any quotes or ampersands.