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craig811's avatar
craig811
Helper III
6 years ago
Solved

How do I create a custom function in column 2

Hi,

 

I have an account in column 2 in my table : 

054.051.0540000.0800000.056.1234.0000

 

Can I write a custom function to pull the fourth segment: 0800000 and replace the last three digits with segment five:056 so when I call the function it will provide me the value: 0800056 ?

 

Thank you 

  • Hi craig811 

    1. Create a blank query

    2. Open the advanced editor, delete the code shown and paste this code instead:

     

    (input_ as text)=>
    let 
        list_ = Text.Split(input_,"."),
        output_ = Text.Start(list_{3},Text.Length(list_{3}) - 3) & list_{4}
    in
        output_

     

    3. Name the query with the name you want for the function, for instance myFunction_

    4. In your original query, add acustom column with the code (assuming Column2 is where you have the data you want to apply the function to)

    = myFunction_([Column2])

    Please mark the question solved when done and consider giving kudos if posts are helpful.

    Contact me privately for support with any larger-scale BI needs

    Cheers 

3 Replies

  • AlB's avatar
    AlB
    Community Champion

    Hi craig811 

    1. Create a blank query

    2. Open the advanced editor, delete the code shown and paste this code instead:

     

    (input_ as text)=>
    let 
        list_ = Text.Split(input_,"."),
        output_ = Text.Start(list_{3},Text.Length(list_{3}) - 3) & list_{4}
    in
        output_

     

    3. Name the query with the name you want for the function, for instance myFunction_

    4. In your original query, add acustom column with the code (assuming Column2 is where you have the data you want to apply the function to)

    = myFunction_([Column2])

    Please mark the question solved when done and consider giving kudos if posts are helpful.

    Contact me privately for support with any larger-scale BI needs

    Cheers 

    • craig811's avatar
      craig811
      Helper III

      This is great , how can I make the value show in all of the rows under my new column? Currently it will just show in one.

      • AlB's avatar
        AlB
        Community Champion

        craig811 

        What do you mean? are you just invoking the function with one value or are you creating a new custom column with the call to the function as I indicated earlier?  I need more details/pics to understand what you mean

        Please mark the question solved when done and consider giving kudos if posts are helpful.

        Contact me privately for support with any larger-scale BI needs, tutoring, etc.

        Cheers