Forum Discussion

Anonymous's avatar
Anonymous
Not applicable
6 years ago

Connect to web data source like a folder?

I have some files published using apache and I am accessing them in Power BI with a Web connector. This works fine as long as I know the exact name of the file I want. But in some cases I need to import all the files in the web directory and don't know their names or how many there are.

E.g. my files are at  https://myserver/files/  and I am trying to access all the files in that web server directory in the same fashion as I coudl if using a FOLDER connnector, where I could read all the files in a Windows folder I can't seem to find any references to how to do this. I've see reference to accessing a SharePoint folder but this isn't SharePoint.

Any ideas?

6 Replies

    • ImkeF's avatar
      ImkeF
      Community Champion

      Hi Anonymous ,

      I'm not familiar with it, sorry.

       

    • Anonymous's avatar
      Anonymous
      Not applicable

      Thanks, Greg_Deckler  and ImkeF however I don't need to sync multiple Apache servers. I have files being stored in one server and I can do a scheduled refresh with Power BI re-reading the data periodically.  My challenge is trying to find a way to treat that server directory as if it were a folder on a Windows OS, and have the functionality of a folder connection. That would allow me to get all the files in it, without knowing in advance how many there are, or their exact names. There may not be a way to do it like that.

      • gracez's avatar
        gracez
        Frequent Visitor

        Hi Gitouttatown,

         

        Have you found the solution? I have the same problem getting all files in our server folder. Thank you.

         

         

        Grace Zhang

  • Anonymous's avatar
    Anonymous
    Not applicable

    Hi everybody,

    I'm not sure if this is the same issue that I have: I'm trying to use a function like "Folder.Files" to access a list of files that I have in my web server folder.

    Do you have any idea?

    All best.