Forum Discussion
Substrac two rows from same column
Hello,
I need some help guys,i have this main table :
I need to substract (Bike-A)- (Bike-B) if the result is negative so we display Category which is Bike,Bus,Car, i'll write you an exp :
(Bike-A)- (Bike-B)=1 (Ok)
(Bus-A)- (Bus-B)=10 (Ok)
(Car-A)- (Car-B)=-1<0 so we display the category (Car)
what i did i concate category and type as shown below :
i tried several formula but i didn't get the right result,any help please ?
what i need is : if([Bike-A] - [Bike-B]<0 then Bike and the same for other.
Thank you 🙂
Hi, FZOU
It’s my pleasure to answer for you.
According to your description, I think you can create a measure to calculate the correct result.
Like this:
Measure = VAR a = MAXX ( FILTER ( ALL ( Table2 ), Table2[Type] <> SELECTEDVALUE ( Table2[Type] ) && Table2[Category] = SELECTEDVALUE ( Table2[Category] ) ), [Value] ) RETURN IF ( SELECTEDVALUE ( Table2[Type] ) = "A" && SELECTEDVALUE ( Table2[Value] ) - a < 0 || SELECTEDVALUE ( Table2[Type] ) = "B" && SELECTEDVALUE ( Table2[Value] ) - a > 0, SELECTEDVALUE ( Table2[Category] ) )If it doesn’t solve your problem, please feel free to ask me.
Best Regards
Janey Guo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- MFelixSuper User
Believe this post is duplicated with the one below:
https://community.powerbi.com/t5/Desktop/Substract-two-rows/m-p/1442043#M605621
- v-janeyg-msftCommunity Support
Hi, FZOU
It’s my pleasure to answer for you.
According to your description, I think you can create a measure to calculate the correct result.
Like this:
Measure = VAR a = MAXX ( FILTER ( ALL ( Table2 ), Table2[Type] <> SELECTEDVALUE ( Table2[Type] ) && Table2[Category] = SELECTEDVALUE ( Table2[Category] ) ), [Value] ) RETURN IF ( SELECTEDVALUE ( Table2[Type] ) = "A" && SELECTEDVALUE ( Table2[Value] ) - a < 0 || SELECTEDVALUE ( Table2[Type] ) = "B" && SELECTEDVALUE ( Table2[Value] ) - a > 0, SELECTEDVALUE ( Table2[Category] ) )If it doesn’t solve your problem, please feel free to ask me.
Best Regards
Janey Guo
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.