Forum Discussion
Represent assets and liabilities
Hi there,
I have several measures on Power BI:
- Current Assets
- Non-Current Assets
- Current Liabilities
- Non-Current Liabilities
I would like to represent in a graphic where I could be able to compare assets vs liabilities, so in the assets column I would like to see Current Assets + Non-Current Assets and on the liabilities, I would like to see Current Liabilities + Non-Current Liabilities.
Could this be possible?
I would like to achieve something similar to the screenshot attached but of course on the same visual (now they correspond to two different)
Thanks in advance,
maserr how does your table looks like? Do you have something that identifies what is Assets and Liabilities, which can be used on x-axis to group these together?
Hi maserr
If you want to compare assets vs liabilities, you can create two measure
Measure = [Current Assets]+[Non-Current Assets] Measure 2 = [Current Liabilities]+[Non-Current Liabilities]Or you can add a filter
Current = SWITCH(SELECTEDVALUE('Table 2'[cate]),"Assets",[Current Assets],"Liabilities",[Current Liabilities]) non-current = SWITCH(SELECTEDVALUE('Table 2'[cate]),"Assets",[Non-Current Assets],"Liabilities",[Non-Current Liabilities])Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.
2 Replies
- v-juanli-msft
Community Support
Hi maserr
If you want to compare assets vs liabilities, you can create two measure
Measure = [Current Assets]+[Non-Current Assets] Measure 2 = [Current Liabilities]+[Non-Current Liabilities]Or you can add a filter
Current = SWITCH(SELECTEDVALUE('Table 2'[cate]),"Assets",[Current Assets],"Liabilities",[Current Liabilities]) non-current = SWITCH(SELECTEDVALUE('Table 2'[cate]),"Assets",[Non-Current Assets],"Liabilities",[Non-Current Liabilities])Best Regards
Maggie
Community Support Team _ Maggie Li
If this post helps, then please consider Accept it as the solution to help the other members find it more quickly.